Answer:
Option (D) i.e., synchronous is the correct option to the following question.
Explanation:
The following statement are the synchronous type of training because it is the type of training which is given to students or the persons for the purpose of knowledge in present time and the trainer or that person who give them information they can receive feedback and message at that time and all persons has permission to ask questions with them.
Option C is incorrect because in this type of training the interaction between the trainer and the receiver could not be established.
Option A is incorrect because the classroom-based training only for that person or the students who are available at that time at that place and in this video conferencing is not available.
Answer:
<h2>I would recommend Python Programming language</h2>
Explanation:
The major reason i recommend python is that It has a ton of resources, and community support, such that it is practically impossible to get stuck while carrying out a project
Python is easy,and lets you build more functions with fewer lines of code.
More so, provides a stepping stone to learning other code and it is a very flexible language
The answer is Laser Printer. It is a non impact printer that creates characters and images with dots by using a drum and toner. The main advantages of laser printers are speed, precision and economy. A laser can move very quickly, and because the laser beam has an unvarying diameter, it can draw more precisely, without spilling any excess ink.
Answer:
Based on the requirements indicated in the question above, the best Local Area Network (LAN) operating system that can be used is
Windows 7 , 8.1 or Windows 10. This is because they all are configured to handle extensive LAN activity and can connect over 200 users.
Explanation:
Generally speaking, Windows 10 packs more improvement over the previous windows.
Cheers
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
