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Valentin [98]
2 years ago
12

At a red traffic light, you must stop__

Computers and Technology
2 answers:
Anastasy [175]2 years ago
6 0

The answer is D

I have to put 20 characters but it's D because RED means stop no matter what. Although there are very few exemptions none of those are listed.

harina [27]2 years ago
3 0
I would assume the answer is D.
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Types of Computer games​
kiruha [24]

\bold{Hello}~

\bold{Answer:}

<h3>Types of Computer games</h3>
  • Action
  • Adventure
  • Simulation
  • Sports
  • Role-playing
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  • Party games

<em>(</em><em>That's</em><em> </em><em>all</em><em> </em><em>i</em><em> </em><em>know</em><em>)</em><em> </em>

<h2>#Hopeithelps\:</h2>

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5 0
2 years ago
A list of sources used for in-text citations that appears at the end of a document is called:
jolli1 [7]
The correct answer is Works cited page
5 0
2 years ago
The linux and macos program traceroute is known by a slightly different name on windows. it's referred to as ______.
kompoz [17]

The answer is 'tracert'. Tracert or traceroute command is a form of a diagnostic tool which allows you to capture information as the packet is sent from the source and destination providing the route taken and measure of delay across the IP network.

7 0
3 years ago
Add an array, which will store the most recent 5 recent transactions. For the array, add an insert function which will store the
Vika [28.1K]

The answer & explanation for this question is given in the attachment below.

Download docx
4 0
3 years ago
An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .
Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

}

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

else

cout << "Array is not sorted";

}

8 0
3 years ago
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