I need help on this! i did the first part though
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We are given first equation y=x+11.
Second equation is -3x + 7y = 13.
Part A: We need to convert that second equation in slope-intercept form y=mx+b.
In order to convert it in slope-intercept form, we need to isolate it for y.
-3x + 7y = 13
Adding 3x on both sides, we get
-3x+3x + 7y = 3x+13
7y = 3x +13.
Dividing both sides by 7, we get
7y/7 = 3x/7 +13/7.
<h3>y= 3/7 x + 13/7.</h3>Slope for first equation y=3/7 x +11 is 3/7 and slope of second equation y= 3/7 x + 13/7 is also 3/7.
Slopes are same for both equations.
<h3>Part B: Therefore, lines are parallel due to equal slopes.</h3>