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4vir4ik [10]
3 years ago
8

3. y=37x+11y=37x+11 -3x + 7y = 13 Part A: Convert the second equation to slope-intercept form. Show your work! Part B: Determine

whether or not the graphs of the lines are parallel. Explain how you know.
Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

We are given first equation y=\frac{3}{7}x+11.

Second equation is -3x + 7y = 13.

Part A: We need to convert that second equation in slope-intercept form y=mx+b.

In order to convert it in slope-intercept form, we need to isolate it for y.

-3x + 7y = 13

Adding 3x on both sides, we get

-3x+3x + 7y = 3x+13

7y = 3x +13.

Dividing both sides by 7, we get

7y/7 = 3x/7 +13/7.

<h3>y= 3/7 x + 13/7.</h3>

Slope for first equation y=3/7 x +11 is 3/7 and slope of second equation y= 3/7 x + 13/7 is also 3/7.

Slopes are same for both equations.

<h3>Part B: Therefore, lines are parallel due to equal slopes.</h3>
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