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3 years ago

The most important math skill for making change is

Mathematics

1 answer:

Virty [35]3 years ago

3 0

All of them
But if u had to pick one I would say addition or subtraction

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The radius of the cone is 5 in and y = 13 in. What is the volume of the cone in terms of π?

olga nikolaevna [1]

Answer:

The volume of the cone is;

100 π inches^3

Step-by-step explanation:

To calculate the volume, we need the height

We can get the height from the slant height and the radius

Mathematically, we use Pythagoras’ theorem for this as the slant height, the radius and the height forms a right-angled triangle

The right-angled triangle has the slant height as its hypotenuse

By the theorem, the square of the hypotenuse equals the sum of the squares of the two other sides

Let the height be h

Thus;

12^2 = 5^2 + h^2

169= 25 + h^2

h^2 = 169-25

h^2 = 144

h = √1144 inches = 12 inches

The volume of the cone is;

1/3 * π * r^2 * h

= 1/3 * π * 5^2 * 12

= 100 π inches^3

4 0

2 years ago

yuson must complete 30 hours of community service. she does 2 hours each day. which linear equation represents the hours yuson h

algol [13]

Answer:

30-2x

Step-by-step explanation:

yuson has to finish am total of 30 hours in community service

she does 2 hours each day

in x days, hour of service done=2x

after x days hours of service left=30-2x

therefore the linear equation representing the hours yuson has left after x days is:

30-2x

6 0

2 years ago

Help pls! I can't figure it out

katrin2010 [14]

Answer:

It’s 72
Hope this helps!

5 0

3 years ago

Mariah is a manager of a fitness training center that serves a certain region. She is interested in the amount of water adult re

Luden [163]

Your answer should be B

5 0

3 years ago

Factor the GCF: -6x^4y^5 - 15x^3y^2 + 9x^2y^3

natta225 [31]

<span>-6x^4y^5 - 15x^3y^2 + 9x^2y^3

</span>-6x^4y^5 = -2, 3, x, x, x, x, y, y, y, y, y
15x^3y^2 = -5, 3 x, x, x, y, y
9x^2y^3 = 3, 3 x, x, y, y, y

Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2

Divide that out and we get
$\frac{-6x^4y^5 - 15x^3y^2 + 9x^2y^3}{-3x^2y^2} =$
$2x^2y^3 + 5x - 3y$
$-3x^2y^2(2x^2y^3 + 5x - 3y)$

5 0

3 years ago