25/28 - 2/7
it doesn’t need to be solved because it asked for an expression and not an equation, so no equal sign either
Answer:
18
Step-by-step explanation:
Given that:
y∞ xz
y=kxz. Where k is constant
When z=196 and x= 2 then y= 7
7=(196)(2)k
7=392k
k=1/56
There fore y=(1/56)xz
When x=3 and z =336
y=(1/56)xz
y=(1/56)(336)(3)
y=18
Answer:
2
Step-by-step explanation:
It sounds like we are pretending A is the universe. The only numbers in our world are 1,2,3,4, and 5.
You are given B is all numbers greater than 2.
The complement of B would all the elements not listed in B.
The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.
The elements not in B are 1 and 2.
So B complement is {1,2}.
There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.
Answer:
c is the answer
Step-by-step explanation:
It is the only graph that starts at (1,0)
and if you look closely the slope is 3
Answer:
1. DF (option 3)
2. segment addition postulate
3. segment congruence postulate
4. DF (option 5)
