<span> by taking integral we get
integral sec(x) (tan(x)+sec(x)) dx
applying integral we get
sec(x) (tan(x)+sec(x)) gives sec^2(x)+tan(x) sec(x)
= integral (sec^2(x)+tan(x) sec(x)) dx
Integrate the sum term by term
= integral sec^2(x) dx+ integral tan(x) sec(x) dx
For the integrand tan(x) sec(x), now we will use substitution
substitute u = sec(x) and du = tan(x) sec(x) dx
= integral 1 du+ integral sec^2(x) dx
The integral of sec^2(x) is tan(x)
= integral 1 du+tan(x)
The integral of 1 is u
= u+tan(x)+constant
Substitute the value of u which is equal to
= sec(x):
so our conclusion is
:tan(x)+sec(x)+constant
hope this helps</span>
The answer is
In step 2, the addition property of equality was applied.
In step 4, the division property of equality was applied.
Proof that the answer is correct.
Answer: 9
Step-by-step explanation:
-3 1/3 x (-2 7/10)
-3 = -3*(3/3) = -9/3
-3 1/3 = -10/3
(-2 7/10)
-2 = -2(10/10) = -20/10
-2 7/10 = -27/10
(-10/3)*(-27/10) = (270/30) = 9
Answer:
Kindly check explanation
Step-by-step explanation:
Given the dimension of the dog pen = 30 ft by 40 ft.
Using the knowledge of geometry, that know that a rectangle has been built, the area of the pen should be :
Area of rectangle = Length * width
Area = 40 * 30
Area = 1200 ft²
Perimeter of rectangle = 2(Length + width)
Perimeter = 2(40 + 30)
Perimeter = 2(70)
Perimeter = 140 feets
Hence, area of the pen should be 1200 ft² and its perimeter or fencing should measure 140 feets