How to solve this problem -3 1/3 x (-2 7/10)

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

8 0

Answer: 9

Step-by-step explanation:

-3 1/3 x (-2 7/10)

-3 = -3*(3/3) = -9/3

-3 1/3 = -10/3

(-2 7/10)

-2 = -2(10/10) = -20/10

-2 7/10 = -27/10

(-10/3)*(-27/10) = (270/30) = 9

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Which of the following give an equation of a line that passes through the point (6/5,-19,5) and is parallel to the line that pas

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Parallel lines, have the same slope, so the slope of the line through 0,0 and -2,-12, is the same as for the line running through (6/5,-19.5) as well, so what is it anyway?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 0}}\quad ,&{{ 0}})\quad 
% (c,d)
&({{ -2}}\quad ,&{{ -12}})
\end{array}
\\\\\\
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so, we're looking for the equation of a line whose slope is 6, and goes through (6/5,-19/5)

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ \frac{6}{5}}}\quad ,&{{ -\frac{19}{5}}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\left( -\frac{19}{5} \right)=6\left(x-\frac{6}{5} \right)
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