Question

See attached for the problem

Answer 1

The areas and volumes are given as follows:

a) Area of the four sides to be painted: 2448 m².

b) Area to be covered with shingles: 1140 m².

c) Volume of concrete needed to pour a floor 16 cm deep: 174.72 m³.

d) Total surface area: 5878.4 m².

Area -> Four sides painted

The sides painted are divided as follows:

• Two rectangles of dimensions 26 m and 18 m.

• Two rectangles of dimensions 42 m and 18 m.

Hence the total area to be painted is found as follows:

Total area = 2 x 26 x 18 + 2 x 42 x 18 = 2448 m².

(Area rectangle = base x height)

Area to be covered with shingles

This part of the problem seems incomplete, however the answer is correct.

Volume of concrete

The volume is given by:

Volume = base area x height.

Hence:

• The base area is a rectangle of dimensions 26 m and 42 m.

• The height is of 16 cm = 0.16 m.

Hence the volume is given by:

V = 26 x 42 x 0.16 = 174.72 m³.

Surface area

The base is a rectangular prism of dimensions 26 m, 42 m and 18m, hence:

Surface area base = 2 x (26 x 42 + 26 x 18 + 42 x 18) = 4632 m².

The top is composed by:

• Two rectangles of dimensions 13.6 m and 42 m.

• Two triangles of base 26 m and height 4 m.

Hence:

Surface area top = 2 x 13.6 x 42 + 2 x 0.5 x 26 x 4 = 1246.4 m².

Then the total surface area is:

Total surface area = 4632 + 1246.4 = 5878.4 m².

More can be learned about areas and volumes at brainly.com/question/22070273

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