Solving the system of equations, it is found that x = 3, that is, there are 3 128 MB memory sticks.
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We want to solve for x, thus, in the first equation, we write y as a function of x, that is:
Replacing in the second equation:
x = 3, that is, there are 3 128 MB memory sticks.
A similar problem is given at brainly.com/question/24823220
Answer:
the area is 110. the formula for a trapezoid is <em>A</em><em>=</em><em> </em><em>a</em><em>+</em><em>b</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>h</em><em>.</em><em> </em>
<em>A</em><em>=</em><em> </em><em>a</em><em>+</em><em>b</em><em>/</em><em>2</em><em> </em><em>×</em><em>h</em><em>=</em><em> </em><em>A</em><em>=</em><em> </em><em>9</em><em>+</em><em>1</em><em>3</em><em>/</em><em>2</em><em>×</em><em>1</em><em>0</em><em>=</em><em>1</em><em>1</em><em>0</em>
Use this and explain yourself
7) Area trapezoid = (B+b).H/2, but the Median is equal to (B+b)./ 2
84 =12 . H ==> H = 84/12 ==> H = 7
11) Area Equilateral triangle inscribe in a cercle with Radius R = 2√3
Area = (B.. Altitude) / 2. Calculate H, the altitude. The altitude in an equilateral triangle bisects the opposite side. Apply Pythagoras
(2√3)² = (√3)² + H² ==> 12 = 3 + H² ==> H² = 9 & H = 3
Hence Are = (2√3 x 3) /2 ==> 3√3 unit² or 5.2 unit²
12) Area of regular hexagone with perimeter =12
regular hexagone is formed with 6 equilateral triangles with
each side =12/6 = 2 units
Let's calculate the area of 1 equilateral triangle. Follow the same logic as in problem 11 & you will find that Altitude = √3, Area =(2.√3)/2 =√3 =1.73 Unit³
13) a) Circumference of a circle : 2πR==> 2π(30) =60π = 188.4
b) Area of a circle =πR³ ==> π(30)² = 900π = 2,826 unit²
Answer:
0.06
Step-by-step explanation:
Answer:
669cm2
correct question
Charles drew a regular hexagon and divided it into two identical trapezoid , the side length of the hexagon iscoming16cm,the diagonal shown in fig 30 is 32 cm Charles measure the height of one the trapezoid and found that the height was 13.9 cm find the area of the area
Step-by-step explanation:
The side length of the hexagon should be given which is 16 cm
To get the Length the side length makes with the height of the trapezium, Pythagoras theorem is applied to get the base of the triangle
Base = √((16)^2 - (13.9)^2
Base = √62.29
Base = 7.92cm
Since we have gotten the base
Diagonal - the base gives the top length of the trapezium.
32- 7.92- 7.92 = 16.16
The area of the hexagon gives the 2 times of the trapezium.
To find the area of the trapezium
= 1/2 * ( a+b)h
= 1/2* ( 32+ 16.16)* 13.9
= 24.04*13.9
Area of the trapezium = 334.71cm2
= 334.71 * 2
= 669.42cm2
Hope this helps
