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bazaltina [42]
1 year ago
10

A line goes through the points (−8,−5) and (−10,−6). Find its slope. Enter your answer as a simplified improper fraction, if nec

essary. Do not include "m=" in your answer.
Mathematics
1 answer:
zalisa [80]1 year ago
4 0

Answer:

4/3 i think

Step-by-step explanation:

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a model of an apartment is shown 1\4 in. represents 3 feet in the actual apartment. Find the actual area of the master bedroom
Hatshy [7]

Answer:12 feet by 9 feet


Step-by-step explanation:

1/4 = 3 feet, so every 1/4 of an inch there is three feet, e.g. 3/4 inches of that scale is 9 feet, 1 1/2 inches would be 18 feet, make sense?

8 0
3 years ago
A pattern of ordered pairs is shown.
Anna007 [38]

Answer:

A. is the answer

Step-by-step explanation:

The first numbers are adding 2 and the second number is adding 3, hope this helped, plz brainiest.

8 0
3 years ago
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Which formulas can you use to calculate the volume of a rectangular prism check all that apply
Llana [10]

Answer:

V = Bh

Step-by-step explanation:

5 0
3 years ago
A circle has a radius of 9 cm and a sector of the circle has an arc length of 9. 7cm
frutty [35]

Answer:

S = R θ      where θ is in radians

If θ  = 2 pi then S = 2 pi R       the circumference of the circle

θ = S / R = 9.7 / 9 = 1.08 rad

Since 1 rad = 360 / (2 pi) = 57.3 deg

the angle included = 1.08 rad * 57.3 deg/rad = 61.9 deg

7 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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