Problem
![\frac{1}{6} (x + 12) = - 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B6%7D%20%20%28x%20%2B%2012%29%20%3D%20%20-%204)
Solution
For this case we have the following equation given:
![\frac{1}{6}(x+12)=-4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%28x%2B12%29%3D-4)
We can multiply both sides by 6 and we got:
![x+12=-24](https://tex.z-dn.net/?f=x%2B12%3D-24)
Now we can subtract 12 in both sides and we got:
![x=-24-12=-36](https://tex.z-dn.net/?f=x%3D-24-12%3D-36)
And the solution for this case would be x=-36
Answer:
Step-by-step explanation:
five times a number increased by nine is
5x+9
x is the unknown number being multiplied by 5
increase= add
so add by 9
Answer:
Step-by-step explanation:
Only D has a chance of being correct. 7x means you multiply 7 and whatever x is together.
A and B look like they are added.
C looks like some sort of subtraction has taken place.
D: - 1 * 7 = - 7
4*7 = 28
5*7 = 35
(5, - 27) and ( - 2, 8)
Since both equations express y in terms of x , we can equate the right sides
x² - 8x - 12 = - x² - 2x + 8
rearrange into standard form ( ax² + bx + c = 0 )
2x² - 6x - 20 = 0 ( divide through by 2 )
x² - 3x - 10 = 0
(x - 5)(x + 2) = 0 ( equate each factor to zero and solve for x )
x - 5 = 0 ⇒ x = 5
x + 2 = 0 ⇒ x = -2
Substitute these values into either of the 2 equations for y
x = - 5 → y = 25 - 40 - 12 = - 27 ( using x² - 8x - 12 )
x = - 2 → y = 4 + 16 - 12 = 8
solutions : (5, - 27) or ( - 2, 8 )
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