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MrMuchimi
1 year ago
9

6<-3kWhy is the answer -2Shouldn’t it be positive 2

Mathematics
1 answer:
Marizza181 [45]1 year ago
7 0

we are given the following inequality:

6

To solve for "k" we will divide both sides by -3, since we are dividing by a negative number we will change the direction of the inequality sign, we get:

\frac{6}{-3}>-\frac{3k}{-3}

Solving the operations we get:

-2>k

Therefore, the solution is the numbers that are smaller than negative 2.

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I’ll give you brainless please help me
Papessa [141]

Answer:

I'm pretty sure its 4

6 0
3 years ago
-8x+114=11x+10-11x what's the answer
gtnhenbr [62]
The answer is x=13

I hope this helps!
Ask me for the work!
4 0
3 years ago
Which expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the thi
zaharov [31]

The expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power is; Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power

<h3>How to solve exponents?</h3>

We want to find the expression that is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power.

The sentence above can be expressed as;

((1.5⁵)/(0.7⁴))³

This can be broken down into;

[1.5^(5 * 3)]/(0.7^(4 * 3))

1.5¹⁵/0.7¹²

Looking at the options, the only correct one is;

Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power

Read more about Exponents at; brainly.com/question/11975096

#SPJ1

3 0
2 years ago
Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4
gtnhenbr [62]

Answer:

Simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

Step-by-step explanation:

We need to simplify the expression (6^{-2})(3^{-3})(3*6)^4

Solving:

(6^{-2})(3^{-3})(3*6)^4

Applying exponent rule: a^{-m}=\frac{1}{a^m}

=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\

Factors of 18=2\times 3\times 3=2\times3^2

Factors of 6=2\times 3

Replacing terms with factors

=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\

Using exponent rule: (a^m)^n=a^{m\times n}

=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}

Using exponent rule: a^m.a^n=a^{m+n}

=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}

Now using exponent rule: \frac{a^m}{a^n}=a^{m-n}

=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108

So, simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

7 0
3 years ago
A company is considering adding a new ingredient to its bread recipe to increase the freshness of the bread. To study the
Burka [1]
To study the what ?
8 0
4 years ago
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