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3 years ago

9

Select the true statement. A. Paul's data has a larger overall spread than Sally's data. B. The interquartile range of Paul's da

ta is less than the interquartile range of Sally's data. C. The median of Paul's data is greater than the median of Sally's data. D. The median of Paul's data is equal to the median of Sally's data.

1 answer:

Mila [183]3 years ago

6 0

Answer:

I just did the test and got it right the answer is A. Paul's data has a larger overall spread than Sally's data.

Step-by-step explanation:

You might be interested in

Which strategy would you use to find 2+8? a) doubles plus 1. b)count on. c) doubles. d) doubles minus 1

Gekata [30.6K]

You would count on.

I hope i am right

8 0

4 years ago

What is an estimate for the square root of 150? (Do not find the exact value) Show work

Umnica [9.8K]

Answer:

Somewhere between 12 and 13, perhaps 12.25

Step-by-step explanation:

This is a (rather) simple explanation:

Look for 2 square numbers that are either side of 150

In this case, it is 144 and 169

The square root of 144 is 12 and the square root of 169 is 13

Therefore we can estimate that the square root of 150 is somewhere between 12 and 13.

As 150 is a lot closer to 144 to 169, I would estimate around 12.25 but you do not need an exact value :)

5 0

2 years ago

Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

$16 = a(2)^2 + b(2) + 6$

$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

$10 = 4a + 2b$

$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

$27 = 9a + 3b$

$27 = 3(3a + b)$

$\frac{27}{3} = \frac{3(3a + b)}{3}$

$9 = 3a + b$

$3a + b = 9$ => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

Replace a with 4 in equation 2.

$2a + b = 5$

$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

$b = -3$

The quadratic function that represents the given 3 points would be as follows:

$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

$f(x) = 4x^2 - 3x + 6$

6 0

4 years ago

PLEASE HELP!!!!!!!!!!!!!!

ohaa [14]

In a circle, the arc is two times the length of the angle.

EFG = 98°

98 x 2 = 196

Minor arc EG = 196°

Hopefully this helps :)

3 0

2 years ago

Please help me :( I would Appreciate it

vova2212 [387]

Answer:

I think the answer is C

Step-by-step explanation:

4 0

3 years ago