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Ierofanga [76]
3 years ago
7

What is the slope of a line perpendicular to the line containing the points (4,-7) and (-5,-1)? Express your answer as a common

fraction.
40 POINTS!!!!!!

if not right i report
Mathematics
1 answer:
just olya [345]3 years ago
6 0

Answer:

3/2

Step-by-step explanation:

Slope 1 = (-1+7)/(-5-4) = 6/(-9) = -2/3

Slope 2 perpendicular to Slope 1 :

-1 ÷ -⅔ = 3/2

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Find FL if H is the circumcenter of EFG,
Zanzabum

The artistic crop isn't helpful; it cuts off some vertex names.

The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn.  We have right triangle ELH, right angle L, so

EH² = HL² + EL²

EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339

Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.

Answer: 4.25

8 0
3 years ago
A diameter intersects a semi-circle. What is the arc measure of a semi-circle?
Nesterboy [21]

D. Cannot be determined.

Where does it intersect the semi-circle? If its anywhere then cannot determined.

Hope this helps.

3 0
3 years ago
Find two unit vectors orthogonal to both 8, 5, 1 and −1, 1, 0 .
Elina [12.6K]
In order to do this, you must first find the "cross product" of these vectors. To do that, we can use several methods. To simplify this first, I suggest you compute:

‹1, -1, 1› × ‹0, 1, 1›

You are interested in vectors orthogonal to the originals, which don't change when you scale them. Using 0,-1,1 is much easier than 6s and 7s.

So what methods are there to compute this? You can review them here (or presumably in your class notes or textbook):
http://en.wikipedia.org/wiki/Cross_produ...

In addition to these methods, sometimes I like to set up:
‹1, -1, 1› • ‹a, b, c› = 0
‹0, 1, 1› • ‹a, b, c› = 0

That is the dot product, and having these dot products equal zero guarantees orthogonality. You can convert that to:

a - b + c = 0
b + c = 0

This is two equations, three unknowns, so you can solve it with one free parameter:

b = -c
a = c - b = -2c

The computation, regardless of method, yields:
‹1, -1, 1› × ‹0, 1, 1› = ‹-2, -1, 1›

The above method, solving equations, works because you'd just plug in c=1 to obtain this solution. However, it is not a unit vector. There will always be two unit vectors (if you find one, then its negative will be the other of course). To find the unit vector, we need to find the magnitude of our vector:

|| ‹-2, -1, 1› || = √( (-2)² + (-1)² + (1)² ) = √( 4 + 1 + 1 ) = √6

Then we divide that vector by its magnitude to yield one solution:

‹ -2/√6 , -1/√6 , 1/√6 ›

And take the negative for the other:

‹ 2/√6 , 1/√6 , -1/√6 ›
7 0
3 years ago
Select the equations of f the lines that are parallel to the lines whose equations is y=3x+5
saw5 [17]

Answer:

<h2>y = 3x + b where b is any real number</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

We have the equation: y=3x+5

Parallel lines have the same slope. Therefore the equation of the lines that are parallel to the given line if in form:

y=3x+b

where b is any real number.

5 0
2 years ago
CAN SOMEONE PLS HELP WITH THIS ASAP
DaniilM [7]

Answer:

2,4,5 - obtuse angle

3,4,5 - right angle

6,7,8 - acute angle

7,9,15 - obtuse angle

3,3,10 - cannot form a triangle

5 0
3 years ago
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