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6 months ago

for each compound write a complete reaction equation showing the removal of the atoms that become the water molecule

1 answer:

4 0

Carboxylic group (-COOH) converts into ester (−COCH3) during the reaction of salicylic acid with methanol so, reaction is known as esterification.

The product methyl 2− hydroxyl benzoate is known as the oil of wintergreen. Oil of wintergreen is naturally produced organic ester.

1) Methyl salicylate (oil of wintergreen)

Salicylic acid and methanol undergo esterification reaction in presence of acid catalyst to give methyl salicylate and water.

Salicylic acid is odorless and white Solid Methanol is colourless volatile liquid having pungent odour or smell. Methyl salicylate is colourless liquid having sweet and fruity smell

learn more about esterification reaction at brainly.com/question/13018690

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An unknown quantity of sugar was completely dissolved in water at 75 degrees Celsius to form a clear and colorless solution. The

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Explanation:

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2 years ago

Compared to the nonmetals in Period 2, the metals in Period 2 generally have larger

konstantin123 [22]

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2 years ago

What is meant by the negative sign in an answer like"-46.8kJ"? When would you use a positive sign

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2 years ago

You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the

Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

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2 years ago