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Nesterboy [21]
3 years ago
6

How many molecules are present in 5.45 moles of NO? Use the space below to show your work.

Chemistry
2 answers:
ivann1987 [24]3 years ago
4 0

Answer:

Explanation below:)

Explanation:

5.45 mol NO(6.022*10^23 molecules/mol) = 3.18 *10^24 molecules NO

Good Luck!! :)

tatiyna3 years ago
3 0

Answer:

3.18*10^24 molecules

Explanation:

Since 1 mole of any substance consists of 6.022 × 10²³ molecules, simply do

\frac{5.45 Moles}{1}*\frac{6.022*10^23 molecules}{1 mole}=3.18199*10^24 molecules.

However, remember to include sig figs (3) and round it to 3.18*10^24 molecules

Hope this helps :)

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Answer:

See explanation

Explanation:

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Percentage nitrogen = (2*14.007 amu/ 44.014 amu ) *100% = 63.6%

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Percentage nitrogen = (2*14.007 amu/ 60.064amu)*100% = 46.6%

Percentage hydrogen = (4*1.01 amu/60.064amu)*100% = 6.72%

Percentage carbon = (12.01 amu/60.064amu)*100% = 20.0%

Percentage oxygen = (16 amu/60.064amu)*100% = 26.6%

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Percentage hydrogen = (14*1.01 amu/130.2 amu)*100% = 10.8%

Percentage carbon = (7*12.01 amu/130.2 amu)*100% = 64.6%

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