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Nesterboy [21]
3 years ago
6

How many molecules are present in 5.45 moles of NO? Use the space below to show your work.

Chemistry
2 answers:
ivann1987 [24]3 years ago
4 0

Answer:

Explanation below:)

Explanation:

5.45 mol NO(6.022*10^23 molecules/mol) = 3.18 *10^24 molecules NO

Good Luck!! :)

tatiyna3 years ago
3 0

Answer:

3.18*10^24 molecules

Explanation:

Since 1 mole of any substance consists of 6.022 × 10²³ molecules, simply do

\frac{5.45 Moles}{1}*\frac{6.022*10^23 molecules}{1 mole}=3.18199*10^24 molecules.

However, remember to include sig figs (3) and round it to 3.18*10^24 molecules

Hope this helps :)

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What volume of 0.08892 M HNO3 is required to react completetly with 0.2352 g of potassium hydrogen phosphate?
galina1969 [7]

Answer:

0.0303 Liters

Explanation:

Given:

Mass of the potassium hydrogen phosphate = 0.2352

Molarity of the HNO₃ Solution = 0.08892 M

Now,

From the reaction it can be observed that 1 mol of potassium hydrogen phosphate reacts with 2 mol of HNO₃

The number of moles of 0.2352 g of potassium hydrogen phosphate

= Mass / Molar mass

also,

Molar mass of potassium hydrogen phosphate

= 2 × (39.09) + 1 + 30.97 + 4 × 16 = 174.15 g / mol

Number of moles = 0.2352 / 174.15 = 0.00135 moles

thus,

The number of moles of HNO₃ required for  0.00135 moles

= 2 ×  0.00135 mol of HNO₃

= 0.0027 mol of HNO₃

Now,

Molarity = Number of Moles / Volume

thus,

for 0.0027 mol of HNO₃, we have

0.08892 = 0.0027 / Volume

or

Volume =  0.0303 Liters

8 0
3 years ago
Read 2 more answers
Someone help please.
mojhsa [17]

After 3 half life periods you would have 5 grams of krypton left because half of 40 is 20 half of 20 is 10 and half of 10 is 5

6 0
3 years ago
An object in space is made of gas and gives off light and heat energy. We can only see it at night. Which object is it? (2 point
strojnjashka [21]

Answer:

stars

earth isn't made of gas. (and you can always see it)

moon us not gas, or give off heat

sun is only visible during the day

7 0
2 years ago
Use the following data to estimate ΔHf° for magnesium fluoride. Mg(s) + F2(g) → MgF2(s) lattice energy −2913 kJ/mol first ioniza
miss Akunina [59]

Answer:

The correct answer is -1085 KJ/mol

Explanation:

To calculate the formation enthalphy of a compound by knowing its lattice energy, you have to draw the Born-Haber cycle step by step until you obtain each element in its gaseous ions. Find attached the correspondent Born-Haber cycle.

In the cycle, Mg(s) is sublimated (ΔHsub= 150 KJ/mol) to Mg(g) and then atoms are ionizated twice (first ionization: ΔH1PI= 735 KJ/mol, second ionization= 1445 KJ/mol) to give the magnesium ions in gaseous state.

By other hand, the covalent bonds in F₂(g) are broken into 2 F(g) (Edis= 154 KJ/mol) and then they are ionizated to give the fluor ions in gaseous state 2 F⁻(g) (2 x ΔHafinity=-328 KJ/mol). The ions together form the solid by lattice energy (ΔElat=-2913 KJ/mol).

The formation enthalphy of MgF₂ is:

ΔHºf= ΔHsub + Edis + ΔH1PI + ΔH2PI + (2 x ΔHaffinity) + ΔElat

ΔHºf= 150 KJ/mol + 154 KJ/mol + 735 KJ/mol + 1445 KJ/mol + (2 x (-328 KJ/mol) + (-2913 KJ/mol).

ΔHºf= -1085 KJ/mol

3 0
3 years ago
Help me with 1 and 2
vladimir1956 [14]
B and c are the correct answers
6 0
3 years ago
Read 2 more answers
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