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1 year ago

What value is needed to complete the square? Show all steps. x^2 - 2x +__

1 answer:

7 0

In completing the square method, considering the equation X^2 - 2x + the number to be added should be<u> 1 </u>to make it a perfect square

<h3>How to know term that should added</h3>

The standard quadratic equation is of the form

ax^2 + bx + c

The completing the square method is one of the methods of solving quadratic equations

The factor to be added to the equation while using the completing the square method is of the formula

(b / 2a)^2

compared to the equation in the problem X^2 - 2x +

= (b / 2a)^2

= (2 / 2)^2

= (1)^2

= 1

Learn more on quadratic equations here:

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3 years ago

Solve by completing the square. Round your answers to the nearest tenth and then locate the greater solution. <img src="https://

Andrews [41]

Step-by-step explanation:

Step 1: Write our Givens

${x}^{2} + 10x - 7 = 0$

Move the constant term ,(the term with no variable) to the right side.

Here we have a negative 7, so we add 7 to both sides

${x}^{2} + 10x = 7$

Next, we take the linear coeffeicent and divide it by 2 then square it.

$( \frac{10}{2} ) {}^{2} = 25$

Then we add that to both sides

${x}^{2} + 10x + 25 = 7 + 25$

${ {x}^{2} } + 10x + 25 = 32$

Next, we factor the left,

$(x + 5)(x + 5) = 32$

we got 5 because 5 add to 10 and multiply to 25 as well.

so we get

$(x + 5) {}^{2} = 32$

This is called a perfect square trinomial.

Next, we take the square root of both sides

$x + 5 = ± \sqrt{32}$

± menas that we have a positive and negative solution.

Subtract 5 form both side so we get

$x = - 5± \sqrt{32}$

The greater solution is when sqr root of 32 is positive so the answer to that is

$\sqrt{32} - 5 = 0.7$

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