All categories

3 years ago

What if the value of x? show all work

Mathematics

1 answer:

alina1380 [7]3 years ago

4 0

For this case we can make use of the Pythagorean theorem.
We have then:
(root (117)) ^ 2 = x ^ 2 + 6 ^ 2
Clearing x we have:
x ^ 2 = (root (117)) ^ 2 - 6 ^ 2
Rewriting:
x = root (117-36)
x = root (81)
x = 9
Answer:
The value of x is given by:
x = 9 cm

You might be interested in

the circumfrince of a circle is approximately 100.48 centimeters.the shaded region 3/10 of the whole circle.enter the area of th

Pavlova-9 [17]

Fggdffgdgfdsfsdsfdsdfsdf

4 0

3 years ago

Ashley is riding her bike to train for a triathlon and so far has traveled 96 miles.

Elina [12.6K]

Answer:

6.4

Step-by-step explanation:

she has been riding her bike for 6.4 hours.

7 0

2 years ago

Which angle is adjacent to A. B. C. D.

DaniilM [7]

Angles A F and E should be the answer

8 0

3 years ago

find the volume of a rectangular prism if the length is 3x^2, the width is 2xand the height is x^2+3x+5

nevsk [136]

You are given the length of a rectangular prism of 3x^2, width of 2x and height of x^2 + 3x +5. You are required to find the volume of a rectangular prism. Using the equation V = l x w x h, we multiply the three dimensions.

V = l x w x h

V = (3x^2)(2x)( x^2 + 3x +5)

V = 2x (3x^4 + 9x^3 + 15x^2)

V = 6x^5 + 18x^4 + 30x^3

The volume of the rectangular prism is 6x^5 + 18x^4 + 30x^3.

3 0

2 years ago

If ΔOPQ is dilated from point Q by a scale factor of 3, which of the following equations is true about segment R prime S prime?

Sergio [31]

Answer:

$\overline {R'S'} = 3 {\overline {RS} }$

Step-by-step explanation:

The scale factor of dilation of triangle ΔOPQ, S.F. = 3

The center of dilation = Point <em>Q</em>

Therefore;

The length of the segment, ${\overline {S'Q'} }$ = 3 × The length of the segment, ${\overline {SQ} }$

Similarly;

The length of the segment, ${\overline {R'Q'} }$ = 3 × The length of the segment, ${\overline {RQ} }$

By Pythagoras theorem, we have;

${\overline {R'Q'} }^2 = {\overline {R'S'} }^2 + {\overline {S'Q'} }^2$

Therefore;

${\overline {R'S'} }^2 = {\overline {R'Q'} }^2 - {\overline {S'Q'} }^2 = \left ({3 \times \overline {RQ} } \right) ^2 - \left (3 \times {\overline {SQ} } \right) ^2 = 9 \times \left (\overline {RQ} } ^2 - {\overline {SQ} } ^2 \right) = 9 \times {\overline {RS} }^2$

$\therefore \sqrt{ {\overline {R'S'} }^2} = \sqrt{ 9 \times {\overline {RS} }^2}= 3 \times {\overline {RS} }$

$\overline {R'S'} = 3 \times {\overline {RS} }$ .

6 0

3 years ago