If you would like to simplify the difference <span>(–7x – 5x^4 + 5) – (–7x^4 – 5 – 9x), you can do this using the following steps:
</span><span>(–7x – 5x^4 + 5) – (–7x^4 – 5 – 9x) = -7x - 5x^4 + 5 + 7x^4 + 5 + 9x = 2x^4 + 2x + 10
The correct result would be </span><span>a. 2x^4 + 2x + 10.</span>
Answer:
b
Step-by-step explanation:
cause I smart
Step-by-step explanation:
6 significant figures......
The first term is 2 and the common ratio = -8/2 = -4
S7 = 2 * (-4)^7 - 1
------------- = 6554 answer
-4-1
Answer:

Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using = 
=
= 
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.