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xxTIMURxx [149]
2 years ago
14

Beginning in 2000, an orchestra increased its ticket price by a constant amount each year until 2010.

Mathematics
1 answer:
Scilla [17]2 years ago
6 0

Answer:

$35.50

Step-by-step explanation:

55.50-48= 7.5

2008-2005 = 3

7.5 divided by 3 = 2.5 per year

2005-2000 = 5 multipled by 2.5 = 12.5

48-12.5=35.5

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nata0808 [166]
V= 3.14• 5^2•4
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Sorry I couldn’t give a more detailed explanation but here is the original equation for volume of a cylinder:

V=πr2h

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3 0
3 years ago
Read 2 more answers
What is the volume of a cube with a higher base and width of 4cm
katrin2010 [14]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Volume = height x base x width

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6 0
3 years ago
Madame Dubois bought 20 pearl necklaces for $500. Becoming bored quickly, she sold 3/4 of them at $40 each. She sold the rest at
Serjik [45]

$725


3/4 of 20 = 15 necklaces

15 x 40 = 600


The rest:

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4 0
3 years ago
Read 2 more answers
(5x^5) - (80x^3)<br> factoring
elena55 [62]

Answer:

Factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

Step-by-step explanation:

We need to factor the term (5x^5) - (80x^3)

First we can see that 5x^3 is common in both terms

So, taking 5x^3 common:

(5x^5) - (80x^3)\\=5x^3(x^2-16)

We can write x^2-16 as (x)^2-(4)^2

=5x^3((x)^2-(4)^2)

Now we can solve (x)^2-(4)^2 using the formula: a^2-b^2=(a+b)(a-b)

We can write:

=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)

So, factoring the term (5x^5) - (80x^3) we get \mathbf{5x^3(x-4)(x+4)}

4 0
3 years ago
The usual toll charge over a bridge is $1.50. If you purchase a special sticker for $10.50, the charge is $0.80. At least how ma
Sidana [21]
I believe a minimum of 7 trips over the bridge is required. 

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