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marishachu [46]
1 year ago
12

What is the product?(4y − 3)(2y2 + 3y − 5)8y3 + 3y + 158y3 − 23y + 158y3 − 6y2 − 17y + 158y3 + 6y2 − 29y + 15

Mathematics
1 answer:
motikmotik1 year ago
5 0

We need to find the product of :

\mleft(4y-3\mright)\mleft(2y2+3y-5\mright)

So, the result as following:

\begin{gathered} \mleft(4y-3\mright)\mleft(2y^2+3y-5\mright) \\ =4y\cdot(2y^2+3y-5)-3\cdot(2y^2+3y-5) \\ =8y^3+12y^2-20y-(6y^2+9y-15) \\ =8y^3+12y^2-20y-6y^2-9y+15 \\  \\ =8y^3+6y^2-29y+15 \end{gathered}

So, the answer is the option 4. 8y3 + 6y2 − 29y + 15​

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