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7 months ago

The graph of a sine function g(x) is presented below.

Mathematics

1 answer:

NISA [10]7 months ago

3 0

Solution

To determine the vertical translation

We need to determine the amplitude

The amplitude is

$\frac{10-4}{2}=\frac{6}{2}=3$

Since the minimum is 4

Hence, the Vertical shift is 3+4 = 7

Part B

Given f(x) = 4 sin(θ - 45) + 8

The vertical translation is 8

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CAN SOMEONE HELP ME WITH THIS QUESTION!!!

earnstyle [38]

Answer:

Step-by-step explanation:

let a, b, c represent the number of students in 6th, 7th, 8th grade

ratio of students : teachers = 28 : 1

There are 82 teachers , so 28 × 82 = 2296 students

Then

a + b + c = 2296 , that is

828 + b + c = 2296 ( subtract 828 from both sides )

b + c = 1468 → E

8 0

2 years ago

A bakery sold a total of 400 cupcakes in a day, and 43% of them were vanilla flavored. how many of the cupcakes sold that day we

garik1379 [7]

The number of the cupcakes sold that day that were vanilla flavored is 172.

<h3>How do we calculate a number from a percentage?</h3>

The number of the cupcakes sold that day that were vanilla flavored can be calculated using the following formula:

Number of vanilla flavored cupcakes sold = Total number of cupcakes sold * Percentage that were vanilla flavored .............. (1)

Substituting the relevant values into equation (1), we have:

Number of vanilla flavored cupcakes sold = 400 * 43% = 172

Learn more about percentages here: brainly.com/question/14801224.

#SPJ1

7 0

1 year ago

Which expression has a positive quotient?

Dimas [21]

A because two negatives make a positive

4 0

3 years ago

Read 2 more answers

When you form general ideas and rules based on your experiences and observations you call that form of reasoning

lutik1710 [3]

You could probably call it INDUCTION

8 0

2 years ago

Read 2 more answers

If x>2,then x2-x-6/x2-4=

statuscvo [17]

$\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)$
$---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

6 0

3 years ago