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liq [111]
1 year ago
14

The line segment AB is rotated clockwise about the origin through 360° Identify thecoordinates of the end points of the transfor

med figure

Mathematics
1 answer:
Reil [10]1 year ago
4 0

Explanation

In the question, we are asked to rotate the line segmenT AB clockwise about the origin through 360 degrees.

The first step is to find the current coordinates of the figure. This is given as;

A(-3,3)\text{ and B(1,3)}

Since the object is rotated 360 degrees it implies turning around until you point in the same direction again. Simply put, the previous x and y coordinates of the points of the line segments will remain the same.

Therefore, the answer is:

A(-3,3)\text{ and B(1,3)}

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You start at (2, 10). You move down 4 units. Where do you end?
IgorLugansk [536]

Answer:

(2, 6)

Step-by-step explanation:

coordinates work by (x, y)

so if up or down = y

then 10 - 4 = 6

therefore the answer is (2, 6)

6 0
3 years ago
If A=(-1,-3) and B=(11,-8), what is the length of line ab?
agasfer [191]

Hi!

A=(-1,-3) \ and \ B=(11,-8)\\\\|AB|=\sqrt{(11-(-1))^2+(-8-(-3))^2}\\\\|AB|=\sqrt{(11+1)^2+(-8+3)^2}\\\\|AB|=\sqrt{12^2+(-5)^2}\\\\|AB|=\sqrt{144+25}\\\\|AB|=\sqrt{169}\longrightarrow\boxed{|AB|=13}

7 0
3 years ago
Read 2 more answers
The weight of a newborn baby panda weights 2.2 x 10-1 pounds. If an adult panda can weigh up to 1.2103 times more than a newborn
mylen [45]

Answer: 0.4862\ \text{Pounds}

Step-by-step explanation:

Given

Weight of a newborn baby is 2.2\times 10^{-1}\ \text{pounds}

If an adult panda weighs up to 1.2103 times more than a newborn panda

Then weight of an adult is given by

\Rightarrow 2.2\times 10^{-1}+2.2\times 10^{-1}\times 1.2103\\\Rightarrow 2.2\times 10^{-1}+2.6626\times 10^{-1}\\\Rightarrow 0.4862\ \text{Pounds}

4 0
3 years ago
The following table relates the weights and
MA_775_DIABLO [31]

The probability of randomly chosen tall and obese individuals is 0.30.

Firstly complete the given table and find the total of each row and column.

                 Tall   Medium   Short   Total

Obese             18       28      14  60

Normal           20       51     28         99

Underweight   12       25       9  46

Total          50        104     51 205

We have to find P(Tall | Obese).

P(Tall | Obese) =  P(Tall and Obese) / P(Obese)

Now, P(Tall and Obese) = 18 ÷ 205

And, P(Obese) = 60÷205

Substituting the above values,

P(Tall | Obese) =  18÷205/ 60÷205

P(Tall | Obese) = 18/60

P(Tall | Obese) = 0.30

Hence the probability of a tall and obese individual is 0.30.

To learn more about probability, visit: brainly.com/question/11234923

#SPJ9

8 0
1 year ago
HELP ASAP ASAP HELP ASAP
exis [7]

Answer:

C = x > 6 or x < 1

Step-by-step explanation:

4x + 10 < 14

- 10. - 10

4x < 4

4x / 4 < 4 / 4

x < 1

6 0
3 years ago
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