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3 years ago

Whats greater 9.354 or 9.012

Mathematics

1 answer:

babymother [125]3 years ago

5 0

Answer:

9.354

Step-by-step explanation:

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WHAT IS 9x 3/5 IN FRSCTION FORM NEED HELP THASNK you

asambeis [7]

Answer:

27/5 or 5 2/5

Step-by-step explanation:

Assuming you mean 9 x 3/5

The answer would be

27/5

in Decimals, it would be

5.4

and in mixed numbers form it would be

5 2/5

8 0

3 years ago

determinati cel mai mic multiplu comun al urmatoarelor numere naturale a-36,48,54;b-30,45,75;c-48,60,72;d-90,24,72;e-75,100,150;

fenix001 [56]

f-72,108,144 is the answer i hop it helps you

8 0

3 years ago

-36 ÷ 4 A) 4 groups of 9 negatives B) 4 groups of 9 positives C) 9 groups of 4 negatives D) 9 groups of 4 positives

Valentin [98]

Answer:

A) 4 groups of 9 negatives

Step-by-step explanation:

-36/4

-9

This means we have 4 groups of 9 negatives

7 0

3 years ago

Work out the height of a triangle with base b= 7.7mm and area a=164.78mm2

solong [7]

Answer:

21.4 mm

Step-by-step explanation:

area ÷ base = height

164.78 mm^2 ÷ 7.7 mm

21.4 mm

Check:

base • height = area

7.7 mm • 21.4 mm = 164.78 mm^2

5 0

3 years ago

The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50

Natali5045456 [20]

Answer:

(a) See Explanation

(b) $\bar x =50$ and $\sigma_x = 0.8944$

(d) $P(\bar x > 55) = 0$

Step-by-step explanation:

Given

$\mu = \$50$ -- mean

$\sigma = \$20$ --- standard deviation

$n=500$ --- sample size

Solving (a): The reason we can't determine the probability that an amount to access internet by a household will exceed $55.

The question says that a lot of households pay low rates, but the percentage of the households in this category is not given. This means that it is impossible to determine the shape of the distribution.

Hence, the probability cannot be calculated.

Solving (b): Sample mean and Sample standard deviation

The sample mean estimates the population mean

So:

$\bar x =\mu$

$\bar x =50$

The sample standard deviation is calculated as thus:

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{20}{\sqrt{500}}$

$\sigma_x = \frac{20}{22.36}$

$\sigma_x = 0.8944$

Solving (c): The shape of the distribution.

We have:

$n = 500$ --- The sample size

According to Central limit theorem, When the sample size is greater than 30, then the shape of the distribution is normal.

Hence, the shape is normal

Solving (d): $P(\bar x \ge 55)$

Calculate the test statistic (t)

$t = \frac{\bar x - \mu}{\sigma}$

$t = \frac{55 - 50}{0.8945}$

$t = \frac{5}{0.8945}$

$t = 5.590$

So:

$P(\bar x > 55) = P(t > 5.590)$

Referencing the z table, we have:

$P(t > 5.590) = 0$

Hence:

$P(\bar x > 55) = 0$

5 0

3 years ago