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dybincka [34]
1 year ago
6

Write a linear equation that has m=-4 and passes through (5,9)!

Mathematics
1 answer:
sladkih [1.3K]1 year ago
4 0

Answer:

y=-4x+29

Step-by-step explanation:

Using point-slope form,

y-9=-4(x-5) \\ \\ y-9=-4x+20 \\ \\ y=-4x+29

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I need geometry help...
Amiraneli [1.4K]
Sin(h) = 8/17
Hope this helps

6 0
3 years ago
There are 600 seatsin a auditorium.450 people are coming. Meals for 3/4 of the 600 are prepared. Dessert for 5/8 of the 600 are
abruzzese [7]

Answer:

idk

Step-by-step explanation:

4 0
4 years ago
What is the range of h
soldi70 [24.7K]

Answer: Choice D) The h(x) values -4, -2, 2, 4, and 6

Explanation:

The range is the set of all possible y outputs, or h(x) outputs.

We simply list the y coordinate of each blue point shown on the graph.

We cannot say something like -4 ≤ h(x) ≤ 6 because there are gaps where the function is not defined. For instance, h(x) = 0 is not possible, so 0 is not in the range. Put another way: there is no point with y coordinate 0 on the graph, so that's why 0 is not part of the range.

3 0
3 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
Nataly_w [17]

Step-by-step explanation:

\displaystyle y = Asin(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{\frac{π}{3}}{3} = \frac{π}{9} \\ Period → \frac{2}{3}π

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.

I am joyous to assist you anytime.

5 0
3 years ago
Write the equation of a parabola whose directrix is y=9.75 and has a focus at (8, 0.25).
lana [24]

Answer:

y = (-1/19)(x - 8)² + 1521/76

Step-by-step explanation:

A parabola moves in such a way that it's distance from it's focus and directrix are always equal.

Now, we are given that directrix is y = 9.75 and focus is at (8, 0.25). Focus can be rewritten as (8, ¼) and directrix can be rewritten as y = 39/4

If we consider a point with the coordinates (x, y), it means the distance from this point to the focus is;

√((x - 8)² + (y - ¼)²)

Distance from that point to the directrix is; (y - 39/4)

Thus;

√((x - 8)² + (y - ¼)²) = (y - 39/4)

Taking the square of both sides gives;

((x - 8)² + (y - ¼)²) = (y - 39/4)²

(x - 8)² + y² - ½y + 1/16 = y² - (39/2)y + (39/4)²

Simplifying this gives;

(x - 8)² - (39/4)² = (½ - 39/2)y

(x - 8)² - 1521/4 = -19y

(x - 8)² - 1521/4 = -19y

Divide both sides by -19 to get;

y = (-1/19)(x - 8)² + 1521/76

6 0
3 years ago
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