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1 year ago

Write a linear equation that has m=-4 and passes through (5,9)!

Mathematics

1 answer:

sladkih [1.3K]1 year ago

4 0

Answer:

$y=-4x+29$

Step-by-step explanation:

Using point-slope form,

$y-9=-4(x-5) \\ \\ y-9=-4x+20 \\ \\ y=-4x+29$

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Orlando has 24 apps and Maria has 10.

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1 year ago

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An item is regularly priced at 60 . It is on sale for 40 percent off the regular price. How much (in dollars) is discounted from

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3 years ago

Negative 5X +3 equals 18

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3 years ago

Rhonda wants to take out a 30-year, $280,000 loan with a 4.4% APR. She is considering purchasing 2 points, which will decrease h

Paha777 [63]

Given Information:

Loan amount = $280,000

Annual Percentage Rate = APR = 4.4% = 0.044

Number of years = 30

Required Information:

Monthly payment with points = ?

Monthly payment without points = ?

Answer:

Monthly payment with points = $1,361

Monthly payment without points = $1,402.13

Step-by-step explanation:

The monthly payment can be found using,

$MP = P\times \frac{r\times (1+r)^{n}}{(1+r)^{n} - 1}$

P is the loan amount.

Where interest rate r is given by

$r = \frac{APR}{12}$

Total number of payments n are given by

$n = 30\times12 = 360$

Monthly payment with points:

Rhonda is considering purchasing 2 points and each decreases APR by 0.125%

So the APR becomes

$APR = 4.4\% - 0.125(2)\\\\APR = 4.4\% - 0.25\%\\\\APR = 4.15\%$

and the corresponding interest rate r is

$r = \frac{APR}{12}\\\\r = \frac{4.15\%}{12}\\\\r = 0.3458\% \\\\r = 0.003458$

Finally, the monthly payment is

$MP =280,000\times \frac{0.003458\times (1+0.003458)^{360}}{(1+0.003458)^{360} - 1}\\\\MP =280,000\times 0.0048608 \\\\MP = \$ 1,361$

Monthly payment without points:

Interest rate r is,

$r = \frac{APR}{12} \\\\r = \frac{4.4}{12} \\\\r = 0.3667\% \\\\r = 0.003667$

Monthly payment is,

$MP =280,000\times \frac{0.003667\times (1+0.003667)^{360}}{(1+0.003667)^{360} - 1}\\\\MP =280,000\times 0.0050076 \\\\MP = \$ 1,402.13$

So monthly payment with points is $1,361 and monthly payment without points is $1,402.13

6 0

3 years ago