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AVprozaik [17]
1 year ago
12

How many different outcomes are there if you roll four four sided dice in the shape of a pyramid

Mathematics
2 answers:
den301095 [7]1 year ago
8 0

Main Answer:16.

Concept and definitions should be there:

Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.

Given that :

A four-sided die in the shape of a pyramid is rolled twice.

Solving part:

The possible outcomes are

{ (1,1),(1,2),(1,3),(1,4)

 (2,1),(2,2),(2,3),(2,4)

 (3,1),(3,2),(3,3),(3,4)

 (4,1),(4,2),(4,3),(4,4) }

Hence we can conclude that the number of possible outcomes on rolling a four sided die twice is 16.

Final Answer: 16.

To learn about more about the probability visit: brainly.com/question/27694535 #SPJ9.

Eva8 [605]1 year ago
3 0

A four sided dice 4 different faces which provide 4 different outcomes

So total number of cases in this case will be 4

Now, it is given that it is in the shape of a pyramid

Thus the base will have almost negligible chance of coming

thus let 3 sides be the sides which can come up

Thus probability of these 3 sides coming will be 1/3

Thus the probability of any 3 numbers showing except for the number on the base will be 1/3

#SPJ9

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Answer:

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Step-by-step explanation:

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Snowcat [4.5K]

Answer:

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Step-by-step explanation:

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What are the amplitude, period, and midline of f(x)=-4 cos (2x-n)+3?
tangare [24]
To find the amplitude and period you need to be familiar with the following equation. Also you need to know that the standard cos has a period of 2\pi and the midline is a line that runs between the max and min of the y-values of the function.

Equations:
f(x) = A cos(Bx +C) + D
f(x) = -4 cos(2x -n) + 3

A = amplitude = |-4| = 4
B = 2
C = phase shift = n = 0 
D = vertical shift = midline = 3

Amplitude = 4

Find the period:
Period = \frac{2\pi}{B} = \frac{2\pi}{2} = \pi

Find the midline:
We know that the amplitude is 4  so we have a range from -4 to 4. The standard y = cos(x) has its midline at 0 so y = 0. This is also true for y = -4 cos(x). In your equation though, you have a vertical shift of +3 so this changes our midline. With an amplitude of 4, which gives us a range from -4 to 4(our y-values), the shift moves this up by 3 so that means we will have new y-values and a range of -1 to 7. Now we need to find the midline(the middle of our y-values) of our new range. We can find this by using the following formula
Midline = \frac{Y_1 + Y_2}{2} = \frac{-1+ 7}{2} = \frac{6}{2} = 3

Midline:
y = 3

Note, in the following equations that D = 3 = midline

y = A (Bx+C) + D
y = -4 (2x + n) + 3

Also, the picture that is attached is what your equation looks like when graphed.


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Step-by-step explanation:

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