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Zielflug [23.3K]
3 years ago
15

Help plzz Find the slope of the line that contains the points (-2, 5) and (-1, 7)

Mathematics
2 answers:
larisa86 [58]3 years ago
7 0
Use the slope formula.
Subtract the y-coordinates.
Subtract the x-coordinates in the same order.
Divide the difference in y by the difference in x.

slope = m = (y2 - y1)/(x2 - x1)

slope = (5 - 7)/(-2 - (-1)) = -2/(-1) = 2

slope = 2
pychu [463]3 years ago
6 0
(-2, 5) ve (-1, 7)
y₁ = 5
y₂ = 7
x₁ = -2
x₂ = -1

m = (y₂-y₁)/(x₂-x₁)
m = (7-5)(-1 (-2))
m = 2/(-1+2)
m = 2/1
m = 2
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Answer:

  put all of the expressions into the same form, such as standard form

Step-by-step explanation:

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Finally, you can look a the constant term. Any answer choice that doesn't have a constant term of +4 will be rejected.

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Step-by-step explanation:

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Solve 5x^2-2=-12 by taking the square root
k0ka [10]

Answer:

x = ±i√2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
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  4. Multiplication
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Multiplication Property of Equality

Division Property of Equality

Addition Property of Equality

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<u>Algebra II</u>

Imaginary root <em>i</em>

  • <em>i</em> = √-1

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

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<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Addition Property of Equality] Add 2 on both sides:                                    5x² = -10
  2. [Division Property of Equality] Divide 5 on both sides:                                 x² = -2
  3. [Equality Property] Square root both sides:                                                    x = ±√-2
  4. Rewrite:                                                                                                             x = ±√-1 · √2
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Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

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2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

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The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

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Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

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Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

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3 years ago
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