\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
Okay, so YZ = 3 cm. You have XM correct. And YM = 0.5.
Now, you have the midpoint M at the correct spot.
Use Pythagorean's theorem o find the length of AB. a² + b² = c² a=6, b=8.
6² = 36 8² = 64 36 + 64 = 100 AB = 10!
If AB = 10 then AM = 5 MB also = 5
If B is the midpoint of AC, C would be 12 rows down from A, and 16 columns to the right. The last spot where the line intersects.
There are your answers!
Answer:
A, 1,2
Step-by-step explanation:
we translate it first into language of math
we use n for the number
n² = 3n - 2
then, do some algebra things
n² - 3n + 2 = 0
then factorize it
(n - 2)(n - 1) = 0
first n
n - 2 = 0
n = 2
2nd n
n - 1 = 0
n = 1
so n can be 1 or 2
Answer:
1.20
Step-by-step explanation:
Because .2 is in the tenths place and 0 is the hundredths so you round the hundredths to the tenths and since its 0 then it stays the same.
Answer:
She divided the coefficients incorrectly
Step-by-step explanation:
A. She divided the coefficients incorrectly.
B. She added the exponents instead of subtracting them.
C. She divided the coefficients instead of subtracting them.
D. She subtracted the exponents instead of dividing them.
Correct calculation:
3x³/12x^-2
= 3x³ ÷ 12x^-2
= 3x³ ÷ 1/12x²
= 3x³ × 12x²/1
= 36x^5
Tyna's calculation:
3x³/12x^-2 = x/4
