Here the question is simple.
All because, we only need to find the value of x.
We are given two equations.
5x + 6 = 10 and 10x + 3 =?
So, we will find the the value of x in the first equation, so that we can substitute the value of x in the second one and there we are with the answer.
5x + 6 = 10
For finding the value of x, all we have to do is,
Transpose the number 6 to 10
Therefore. 5x = 10 - 6 ( Take the equal sign as The Magic Bridge on which if anyone crosses it , will change its sign.)
So we have,
5x = 4
So x = 4/5 ( Multiplication will change to division after crossing the equal sign)
( Doubtful? Substitute the value of x and try!)
Now that we got the value of x,
We can just simply substitute the value of x in the second equation.
10x + 3 = ?
x = 4/5
10*4/5 +3 => 5 and 10 get canceled to 2 at the numerator.
By normal multiplication and then addition, we will get,
8 + 3 = 11
Hope this helps!!!! :)
Answer:
(4,4)
Step-by-step explanation:
y = 2x - 4 -------eqn 1
4y = x + 12 ------eqn 2
From eqn 1 y = 2x - 4; insert in eqn 2
4 (2x-4) = x + 12 (open the bracket)
8x - 16 = x + 12 (taking like figures to the same side, sign changes)
8x - x = 12 + 16
7x = 28
x = 28/7
x = 4
From eqn 1
y = 2x - 4
y = 2(4) - 4
y = 8 - 4
y = 4
(x,y) = (4,4)
Answer:
-78.12
Step-by-step explanation:
a 12.4x-6.3= -78.12
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Answer:
Step-by-step explanation:
Given that:
The numbers of the possible public swimming pools are 5
From past results, we have 0.007 probability of finding bacteria in a public swimming area.
In the public swimming pool, the probability of not finding bacteria = 1 - 0.007
= 0.993
Thus;
Probability of combined = Probability that at least one public
sample with bacteria swimming area have bacteria
Probability of combined sample with bacteria = 1 - P(none out of 5 has
bacteria)
Probability of combined sample with bacteria = 1 - (0.993)⁵
= 1 - 0.9655
= 0.0345
Thus, the probability that the combined sample from five public swimming areas will show the presence of bacteria is 0.0345
From above, the probability that the combined sample shows the presence of bacteria is 0.0345 which is lesser than 0.05.
Thus, we can conclude that; Yes, the probability is low enough that there is a need for further testing.