Answer:
x = 16
m<Y = 34°
Step-by-step explanation:
∆XYZ is an isosceles ∆. An isosceles ∆ has two equal sides, as well as the bases of the isosceles triangle are congruent. In this case, therefore:
<X = <Z
(6x - 23)° = (4x + 9)
Solve for x
6x - 23 = 4x + 9
Collect like terms
6x - 4x = 23 + 9
2x = 32
Divide both sides by 2
x = 16
m<Y = 180° - (m<X + m<Z) (sum of ∆)
m<Y = 180 - ((6x - 23) + (4x + 9))
Plug in the value of x
m<Y = 180 - ((6(16) - 23) + (4(16) + 9))
m<Y = 180 - (73 + 73)
m<Y = 34°
0
evaluate g(7) by substituting x = 7 into g(x
g(7) = (49-35-10)/2 = 4/2 = 2
now substitute x = 2 into f(x)
f(2) = √(4 - 48 + 144) = √0 = 0
(f ○ g)(7) = 0
Answer: x=14
Step-by-step explanation: have a good day
Pythagorean TheoremIn a right triangle, the sum of the squares of the legs equals the square of the hypotenuse."Special Triangles"<span>3-4-5
5-12-13
7-24-25
8-15-17</span>Converse of the Pythagorean ConjectureIf the lengths of a triangle satisfy the Pythagorean Theorem, then the triangle is a right triangle.Isosceles Right Triangle ConjectureIn an isosceles right triangle, if the legs have length x, then the hypotenuse has length x-root-2.30-60-90 Triangle ConjectureIn a 30-60-90 triangle, if the shorter leg has length x, then the longer leg has length x-root-3 and the hypotenuse has length 2x.Rationalizing the DenominatorEquation for a Circlea squared + b squared is less than c squaredObtuse trianglea squared + b squared is greater than c squaredAcute triangle
Answer:
(a) 
(b) 
<em>(b) is the same as (a)</em>
(c) 
(d) 
(e) 
Step-by-step explanation:
Given

Solving (a): Probability of 3 or fewer CDs
Here, we consider:

This probability is calculated as:

This gives:


Solving (b): Probability of at most 3 CDs
Here, we consider:

This probability is calculated as:

This gives:


<em>(b) is the same as (a)</em>
<em />
Solving (c): Probability of 5 or more CDs
Here, we consider:

This probability is calculated as:

This gives:


Solving (d): Probability of 1 or 2 CDs
Here, we consider:

This probability is calculated as:

This gives:


Solving (e): Probability of more than 2 CDs
Here, we consider:

This probability is calculated as:

This gives:

