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aliya0001 [1]
1 year ago
8

What is three squared minus two thirds?

Mathematics
1 answer:
Tems11 [23]1 year ago
5 0

three squared minus two thirds

3^2-\frac{2}{3}

three square = 3 x 3 = 9

\begin{gathered} 3^2-\frac{2}{3}=9-\frac{2}{3} \\ 3^2-\frac{2}{3}=\frac{9}{1}-\frac{2}{3} \end{gathered}

Least common factor of 1 and 3 is 3

\begin{gathered} 3^2-\frac{2}{3}=\frac{9}{1}-\frac{2}{3} \\ 3^2-\frac{2}{3}=\frac{27-2}{3} \\ 3^2-\frac{2}{3}=\frac{25}{3} \end{gathered}

Three squared minus two third is twenty five by three.

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Can someone please help me!!
Vladimir [108]

Answer:

#18)  <em>m</em>∠B = 107°

#19) <em>m</em>∠B = 17°

Step-by-step explanation:

*Supplementary angles are angles who's measures equal 180°

*Complementary angles are angles who's measures equal 90°

#18) If ∠A is 73°, then we must subtract 73 from 180.

180 - 73 = 107

This means that <em>m</em>∠B = 107°.

#19) If ∠A is 73°, then we must subtract 73 from 90.

90 - 73 = 17

This means that <em>m</em>∠B = 17°.

8 0
3 years ago
Minh wrote the following number sentence 2.6 + 0.33= 59. Use estimation to show that Minh's answer is incorrect.
Ne4ueva [31]
2.6 rounds to 3, and 0.33 would round to 0.50. Adding 3 and 0.50 together would equal to 3.50. 59 and 3.50 are no where near to each other which concludes Minh is incorrect.
(Please mark me brainliest)
3 0
3 years ago
In her first 20 games, Jennie served 4 aces. If she continues to serve aces at this rate, how many aces will she have after 160
Talja [164]

Answer:

32 aces

Step-by-step explanation:

4/20= x/160

once you set up this proportion you can cross multiple to get:

20x= 640

then just solve for x:

x= 32

5 0
3 years ago
Which of the following are even numbers ?
musickatia [10]

Answer:

an even number is a number that is divisible by 2 so there it will be 16 38 44 48 68 84 and 92

3 0
3 years ago
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

8 0
3 years ago
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