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vazorg [7]
3 years ago
15

Find the measure of the angle indicated

Mathematics
1 answer:
Grace [21]3 years ago
6 0

Answer:

86

Step-by-step explanation:

y + 28 + 58 = 180

y + 86 = 180

y = 180 - 86

y = 94

x + y = 180

x + 94 = 180

x = 180 - 94

x = 86

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Can someone please help me factor and write the equations for these two problems ?
prisoha [69]

Answer:

Step-by-step explanation:

Asymptotes 3

g(x) = \frac{3x}{x^2-3x-10}

Factors of denominator will be,

x² - 3x - 10 = x² - 5x + 2x - 10

                 = x(x - 5) + 2(x - 5)

                 = (x + 2)(x - 5)

Therefore, factored form of g(x) will be,

g(x) = \frac{3x}{(x + 2)(x - 5)}

Asymptotes 4

h(x) = \frac{(x-5)}{x^{2} + 14x + 40}

      = \frac{x-5}{x^{2}+10x+4x+40}

      = \frac{x-5}{x(x+10)+4(x+10)}

      = \frac{x-5}{(x+10)(x+4)}

5 0
3 years ago
What is wrong with this histogram?
Marta_Voda [28]
The intervals along the x axis are inconsistent. the one that says 21-30 should either be split into 2 or have twice the width.

Hope this helps :)
3 0
3 years ago
A basketball player's free throw percentage is 82.5%, or 0.825.
Ivanshal [37]

Answer:

The 5 is in the thousandths place.  

825/1000

Step-by-step explanation:

Simplified this would be 33/40

825/1000  Divide the top and bottom by 25

3 0
1 year ago
Referring to the Fig. in Question #40, find the unknown<br> length Y.
icang [17]

Answer:

tan30°=7/x

\frac{1}{ \sqrt{3} }  =  \frac{7}{x }  \\ x = 7 \sqrt{3}

cos30°=x/y

\frac{ \sqrt{3} }{2}   =  \frac{7 \sqrt{3} }{y}  \\  \\ 7 \sqrt{3}  \times 2 =  \sqrt{3}  \times y \\ \frac{7 \sqrt{3 }  \times 2}{ \sqrt{3} }  = y \\7 \times 2 = y \\ 14 = y

tell me if it's wrong.

7 0
2 years ago
Read 2 more answers
Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?
zmey [24]

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

<h3>on what interval is the function positive?</h3>

The function is positive when g(x) > 0.

Then we need to solve:

∛(x - 3) > 0

We can directly remove the cubic root, because it does not affect the sign of the argument, then:

x - 3 > 0

x > 3

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

If you want to learn more about functions:

brainly.com/question/2456547

#SPJ1

5 0
2 years ago
Read 2 more answers
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