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salantis [7]
3 years ago
10

How is the distributive property used when multiplying two binomials

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

Step-by-step explanation:

When multiplying a binomial times a binomial, each term of the first binomial must be multiplied by each term of the second binomial. Like terms are then combined.

When multiplying two binomials, four multiplications must take place. These multiplications can occur in any order, as long as each of the first two terms is multiplied by each of the second two terms.

There are numerous ways to set up the multiplication of two binomials. The two basic formats, horizontal line-up and vertical line-up, are similar to what we saw in adding and subtracting polynomials. Let's investigate the simple product (x + 2)(x + 4) with a variety of set-ups. Start with the first term of the first binomial (the blue x).

• Distribute (multiply) this term times EACH of the terms in the second binomial (x + 4).

• Then take the second term in the first binomial (including its sign: +2) and distribute (multiply) this term times EACH of the terms in the second binomial (x + 4).

• Add the results, combining like terms when needed.

• This method will work with all polynomials, not just binomials times binomials.

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Which will result in a difference of squares?
otez555 [7]

Expanding the given expressions using Foil:

1)(–7x + 4)(–7x + 4) =7x^{2}-28x-28x+16=49x^{2}-56x+16

2) (–7x + 4)(4 – 7x)=-28x+49x^{2}+16-28x=49x^{2}-56x+16.

3)(–7x + 4)(–7x – 4)=49x^{2}+28x-28x-16=49x^{2}-16.

4)(–7x + 4)(7x – 4)=49x^{2}+28x+28x-16=49x^{2}+56x-16.

The third option that is (–7x + 4)(–7x – 4) is difference of two squares.

5 0
3 years ago
Read 2 more answers
If ∠WOZ and ∠WOX are supplementary angles and ∠WOX and ∠XOY are complementary angles, then what is the value of x and m∠XOY?
omeli [17]

Answer:

D.x = 6; m∠XOY = 18°

Step-by-step explanation:

Supplementary angles add to 180 and complementary angles add to 90

∠WOZ + ∠WOX = 180

108 + ∠WOX = 180

∠WOX + ∠XOY = 90

∠WOX + 3x = 90

∠WOX  = 90 -3x

Replace WOX in the first equation

108 + ∠WOX = 180

108 + 90 -3x = 180

Combine like terms

198 -3x = 180

Subtract 198 from each side

-3x = 180-198

-3x = -18

Divide by -3

-3x/-3 = -18/-3

x = 6

∠XOY  = 3x = 3*6 = 18

5 0
3 years ago
2. Find the compound interest on Rs.25, 000 after 2 years compounded
Allushta [10]

Answer:25,000 in 2 years at annual compound interest, if the rates for the successive years be 4% and 5% per annum respectively is: (1) Rs. 30,000 (2) Rs. 26,800 fa) Rs.

A=P[1+  

100

r

​  

]  

n

 

⇒  A=Rs.25,000×(  

100

106

​  

)  

3

 

⇒  25,000×  

50

53

​  

×  

50

53

​  

×  

50

53

​  

 

⇒  A=Rs.29,775.40

⇒  CI=A−P

⇒  Rs.29,775.40−Rs.25,000

∴   CompoundInterest=Rs.4775.40.

6 0
3 years ago
Solve the proportion x/18=7/21​
Crank

Answer:

x=6

Step-by-step explanation:

4 0
2 years ago
372 picoseconds equal to how many femoseconds
Vlad1618 [11]

Answer:

372,000 femtoseconds

Step-by-step explanation:

<u>1 picoseconds = 1000 femtoseconds</u>

372 picoseconds = 1000 * 372 femtoseconds

1000 * 372

372,000

Answer:  372,000 femtoseconds

5 0
3 years ago
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