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Oliga [24]
4 years ago
8

If G(x) = 3x + 1, then

ddle" class="latex-formula">(1) is

4
1/3
0
Mathematics
1 answer:
Sav [38]4 years ago
3 0

Answer:

0

Step-by-step explanation:

Let (G^-1)(1) = t

Then 1 = G(t)

1 = 3(t) + 1

3t = 0

t = 0

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Answer:6=C 7=C

Step-by-step explanation:

5 0
3 years ago
Which expression and diagram represent “three times a number”?
kozerog [31]

Answer:

You've picked the right one! It's the one you've marked in the picture!

Step-by-step explanation:

Multiplication is just like addition; you're just doing it multiple times instead of once. 3<em>x</em> is equal to <em>x</em> + <em>x</em> + <em>x</em>. That's exactly what the option you chose in the image shows. Great job! You've got this!

6 0
3 years ago
Read 2 more answers
A basketball team played 15 games and won 80% of them. If the team expects to play 30 games in all, how many more games must it
emmainna [20.7K]
So 80% of 15 games won equal 12 games won and 3 lost. This is because 15/10 = 1.5 and 1.5 x 8 =12.
For 30, you do the exact same thing but with 90% instead. 30/10 = 3. 3 x 9 = 27.
So they need to have won 27 games to get a 90% winning percentage out of 30 games.
But since the question asks how many MORE games they need to play, it'll be 27-12 = 15.
So they need to win 15 more games to get a 90% winning percentage
5 0
4 years ago
Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

therefore \int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1

on integrating we get

c=(1/6640)

b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

on doing the integration we get

                        =0.37349

c)

marginal density of X is

f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

solve the above integration we get the answer

e)

P(X>20, 0

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

4 0
3 years ago
Which of the following best describes the vertical cross-section of the cylinder ?
Nina [5.8K]
The answer would be d
6 0
3 years ago
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