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Maru [420]
1 year ago
6

If an arena charges $7. 50 to park in satellite parking and $12. 00 to park in an arena lot, how much will be made from parking

11,000 vehicles at the arena and 4,600 in satellites?.
Mathematics
1 answer:
Oksanka [162]1 year ago
3 0

Parking 11,000 automobiles at the venue and 4,600 in satellites will bring in total $166,500.

<h3>Define multiplication.</h3>

One of the four fundamental mathematical operations, along with addition, subtraction, and division, is multiplication. Multiply in mathematics refers to the continual addition of sets of identical size. Let's use the ice creams as a multiplication example to help us comprehend. There are two such groupings, and each group has ice cream.

Given,

If an arena charges $7. 50 to park in satellite parking and $12. 00 to park in an arena lot,

Multiplying:

$7.5 x 4,600 = satellite parking

$34,500 = satellite parking

The next step is to determine how much it will cost to park in the arena lot.

$11,000 ×12 = arena lot

$32,000 = arena lot

Let's now calculate the entire revenue from parking.

Total earnings equal $132,000 + $34,500.

Amount made in total is $166,500.

In conclusion Parking 11,000 automobiles at the venue and 4,600 in total satellites will bring in $166,500.

To learn more about multiplication, visit:

brainly.com/question/23354835

#SPJ4

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You need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture. How much
ozzi

Answer:

A. 605 mL of the 35% solution

B. 55 mL of the 95% solution

Step-by-step explanation:

It is given that, you need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture.

Let x and y be the amount of 35% alcohol solution and 95% alcohol solution (in mL) respectively.

So,

Amount equation: x+y=660        ...(1)

Alcohol equation : 0.35x+0.95y=0.40(660)\Rightarrow 0.35x+0.95y=264     ...(2)

On solving (1) and (2), we get

0.35(660-y)+0.95y=264

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Now, substitute y=55 in (1).

x+55=660  

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x=605  

Therefore, we need 605 mL of the 35% solution  and 55 mL of the 95% solution.

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