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Lady bird [3.3K]
1 year ago
13

A) NO CHANGE B) are no good anymore. C) become obsolete. D) have lost their charm.

Mathematics
1 answer:
mezya [45]1 year ago
4 0

According to the passage, the correct answer has become obsolete. The correct option is C.

In Given, a passage that is shown in the attached photos.

Option C is the best answer. "obsolete" states clearly and concisely: the idea that skills can become obsolete. The meaning of obsolete is no longer in use as it has been replaced by something new and better or more trendy.

Options other than C are A, B and D are incorrect because they are unclear or because they convey an inappropriate tone for passing.

The correct choice from the given passage is therefore obsolete.

Learn more about passage from here brainly.com/question/12555695

#SPJ4

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Find the value of x. Then, find the measure of each angle.
Talja [164]

Answer:

 

Step-by-step explanation:

 

8 0
3 years ago
Producing a musical costs $88,000 plus $5900 per performance. one sold out performance earns $7500 in revenue. If every performa
yan [13]
X = # of perfomances

y = total amount of money

Income: y = 7500x

Expense: y = 5900x + 88000



Substitution:

7500x = 5900x + 88000

1600x = 88000

x = 55

y = 7500(55) = $412,500

55 performances are needed to break-even.
5 0
3 years ago
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
Find 3/5 - 1/4 <br><br> a 4/9<br><br> b 1/2<br><br> c 2<br><br> d 7/20
Lubov Fominskaja [6]

Answer:

7/20

Step-by-step explanation:

Hope this helped!

7 0
3 years ago
Read 2 more answers
A recipe needs the following dry ingredients: 1/4 cup of flour,3/4 cup of sugar, and 1/4 cup of chocolate chips. How many total
zheka24 [161]
There should be 1 1/4 total cups
4 0
3 years ago
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