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madam [21]
3 years ago
13

How many solutions? 2x + 6 = 3(x + 2) - x

Mathematics
1 answer:
Serjik [45]3 years ago
6 0

Answer:

2x = 2x

Step-by-step explanation:

2x + 6 = 3x + 6 - x

2x = 3x - x(cancel equal terms)

2x=2x

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URGENT!!!!!<br> What is the value is x?<br> A. 5.375<br> B. 5.5<br> C. 11<br> D. 13
vodka [1.7K]

Answer:

value of x is B 5.5

Step-by-step explanation:

B 5.5 value of X

7 0
2 years ago
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.Nisha bought a backpack that was on sale at 35% off for $63. How much was the original price of the backpack?
Vlad [161]

Answer:

$180

Step-by-step explanation:

100%=x

35%=$63

63 x 100=6300/35=$180

3 0
3 years ago
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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
2 years ago
A large company made $6,439,583 last year . what in the value of the 9 in $6,439,583?
Mama L [17]

The value of 9 is 9,000 it’s in the  Thousands place

8 0
2 years ago
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Which of the following is a step in constructing angle bisectors using a compass and straight edge? a Construct a copy of the li
motikmotik

Answer:

start with a line segment to divide into equal parts

Step-by-step explanation:

that's the first step you take before you make the angle bisector because there's no point in doing the other steps before that

8 0
2 years ago
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