Find the slope of the line that passes through (65, 100) and (75, 97).

Three years back , a father was 24 years older than his son .at present,the father is five times as old as the son.how old will

azamat

Answer:

The son is 5 I think

Step-by-step explanation:

24+3=27

27 divided by 5 = 5.4

round 5.4 to 5 since it is under .5

and you get 5

3 0

3 years ago

On Monday, Avi walked from his home to the school track and walked 4 laps around the track for a total of 3.5 miles. On Saturday

anyanavicka [17]

Answer:

3.5 = x + 4*y

4 = 2x + 2*y

Step-by-step explanation:

The total distance ran by Avi is the sum of the distance from his house to the track, and the total distance ran in the tracks (that is, the distance of one lap times the number of laps Avi ran).

If we call 'd' the total distance and 'k' the number of laps, we have the equation:

d = x + k*y

So with the data given, we can have the following system:

3.5 = x + 4*y

4 = 2x + 2*y

In the second equation, we have 2x because Avi ran from his home to the track, and in the end ran back home, so Avi ran the distance x two times.

4 0

3 years ago

Elena is trying to figure out how many movies she can download to her hard drive. The hard drive is supposed to hold 500 gigabyt

soldi70 [24.7K]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Maximum capacity of hard drive = 500 GB

Space used up = 58 GB

Size per movie = 8GB

Number of movies = x

1)

[(Number of movies * size per movie) + used up space] should be less than or equal to the maximum capacity to f the drive.

From Elena's inequality, the total space taken up by movies + used up space is greater than total capacity of hard drive.

That is ;

[(8x + 58 ≤ 500

8x ≤ 500 - 58

8x ≤ 442

x ≤ 442 / 8

x ≤ 55.25

The maximum number of movies Elena can download is 55

8 0

3 years ago

How many 1/2 are in 4 in

Norma-Jean [14]

1/2×4=4 is your answer

4 0

3 years ago

Customers arrive at a service facility according to a Poisson process of rate λ customers/hour. Let X(t) be the number of custom

mash [69]

Answer:

Step-by-step explanation:

Given that:

X(t) = be the number of customers that have arrived up to time t.

$W_1,W_2$ ... = the successive arrival times of the customers.

(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

$E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))$

$= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}$

$= 1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}$

$= 1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}$

Now $P(X(s) \leq 0) = P(X(s) = 0)$

(b) We can Determine the conditional mean E[W3|X(t)=5] as follows;

$E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\ = 1- P (X(s) \leq 2 | X (t) = 5 ) \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}$

Now; $P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)$

(c) Determine the conditional probability density function for W2, given that X(t)=5.

So ; the conditional probability density function of $W_2$ given that X(t)=5 is:

$f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 ) \\ \\ = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)$

7 0

3 years ago