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raketka [301]
1 year ago
14

Stem and leaf plots And box Pls help I have no idea what this is

Mathematics
1 answer:
AlladinOne [14]1 year ago
6 0

Answer:

32

Step-by-step explanation:

The end of the box is at 32.

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When we slice a three-dimensional object, we expose new faces that are two dimensional. The two-dimensional face is called _____
zlopas [31]

Answer:

Cross section

Step-by-step explanation:

Cross section refers to the new two dimensional face exposed when we slice through a three dimensional objects.

It can also be the surface or shape exposed by making a straight cut through something, especially at right angles to an axis.

Cross section is the plane surface(two-dimensional objects) formed by cutting across a solid shape (three-dimensional shape) especially perpendicular to its longest axis.

8 0
3 years ago
Whats the height of the prism
zheka24 [161]

Answer:

oh, you may have forgotten to add the file, you can edit and add it, which i will edit my response and respond.

Step-by-step explanation:

8 0
3 years ago
(12) — (23 + 13i) =<br> Chc
rewona [7]

Answer:

-11 - 13i.

Step-by-step explanation:

(12) — (23 + 13i)

= 12 - 23 - 13i

= -11 - 13i.

4 0
3 years ago
Please help me please!<br> Also, please show your work image shown below in attachment
WINSTONCH [101]

Answer:

see below

Step-by-step explanation:

some of your answers that you currently have are wrong, I'll note those mistakes below

- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio

5x+15 = 5(x+3), not (x+3)(x+5)

ie  \frac{10x^2+20x}{x+2}

we see that 10x can divide the numerator in a whole number ratio

10x^2+20x = 10x(x+2), not (x+2)(x+10)

second mistake: the first binomial expansion is incorrect.

you have the expansion formula right, but you added terms wrong, go look at it again

3. x^2+3x+2/ x^2+5x+6

(x+1)(x+2)/(x+3)(x+2)

(x+1)/(x+3)

4. (x^2+6x+8)/(x^2-16)

(x+4)(x+2)/(x+4)(x-4)

(x+2)/(x-4)

5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator

6. (x^4y^6)^2

(x^4y^6)(x^4y^6) = x^8y^{12}

remember that (x^a)(x^b) = x^(a+b)

or remember that (x^a)^b = x^ab

6 0
3 years ago
6 wrestlers compete in a competition. if each wrestler wrestles one match with each other wrestler, what are the total numbers o
PolarNik [594]

The total number of wrestlers are 6 and each have to wrestle each other wrestler only once.

It means, the first wrestler have 5 opponent, second have 4 opponents , third have three oponenets , fourth have two opponents and the fifth have only one opponent.

So the total number of matches = 5+4+3+2+1 =15

3 0
3 years ago
Read 2 more answers
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