7(x+4)=0
7x+28=0
7x=-28
X=-28/7
X=-4
3/8 this is your answer so yahhh hope this heped
The area between the two functions is 0
<h3>How to determine the area?</h3>
The functions are given as:
f₁(x)= 1
f₂(x) = |x - 2|
x ∈ [0, 4]
The area between the functions is
A = ∫[f₂(x) - f₁(x) ] dx
The above integral becomes
A = ∫|x - 2| - 1 dx (0 to 4)
When the above is integrated, we have:
A = [(|x - 2|(x - 2))/2 - x] (0 to 4)
Expand the above integral
A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]
This gives
A = [2 - 4] - [-2- 0]
Evaluate the expression
A = 0
Hence, the area between the two functions is 0
Read more about areas at:
brainly.com/question/14115342
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Answer:
VK = x = 98 mm
Step-by-step explanation:
TY is the bisector of angle T, so it divides segments of the triangle proportionally. That is, ...
VY/VT = KY/KT
VY = VT·KY/KT = (57 mm)·68/192.2 = 30 mm
Then
VK = VY + YK = 30 mm + 68 mm
VK = 98 mm
Answer:
x=5 is not a problem.
Step-by-step explanation:
x would be 5 thats it.