(16,5) it should be
16 input
5 output
if you went to 5 ont he y-axis and keep going till it hits the line the x seems to be 16.
im deeply sorry if this is wrong.
Answer:
It takes at least 7 months for the cat to be at least 6 kg lighter than the original weight.
Step-by-step explanation:
Use exponential decay formula:
A = P (1-r)t
A = amount decreased to
P = original amount
r = rate of decrease
t = time
6 ≥ 12 (1-0.10)t divide both sides by 12
0.5 ≥ (0.9)t take log of both sides
log (0.5) ≥ log (0.9)t power rule of logs lets the exponent t drop to front of log to become a factor
log (0.5) ≥ t log(0.9) divide both sides by log(0.9) which is negative so reverse the inequality sign
log (0.5) / log (0.9) ≤ t use calculator
6.57 ≤ t
It takes at least 7 months for the cat to be at least 6 kg lighter that original weight.
check:
12 (0.9)7≈ 5.73
12 (0.9)6 ≈ 6.37
The equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0) is 
<h3><u>Solution:</u></h3>
We have to find the equation of a parabola that opens up and has the following x intercepts (-3, 0) and (4, 0)
x-intercepts of the parabola are (−3, 0) and (4, 0)
So, we can form an equation:
Also x = 4
x – 4 = 0
x – 4 = 0 is another factor of quadratic equation.
The quadratic function is:

Hence, the equation of the parabola is 
Y equal to or greater than 5/2x + 5
It is not a factor of x-5.Substitute 5 in the palce of x.Since the value is not equal to x,it is not a factor of x-5.