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NemiM [27]
3 years ago
11

What is 648 divided by 4 in long division?

Mathematics
1 answer:
Rainbow [258]3 years ago
7 0

The answer is 162

I hope this help

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15. Over what range of angles does the value of sin(O) consistently increase?
Ronch [10]

Answer:

D. 0° to 90°

Step-by-step explanation:

If we see curve of sin(o) on coordinate,  we will notice that value of sin curve increases from 0 to 90 degrees and then decreases from 90 to 180 degrees.

Hence option D is correct.

Alternatively

we see that

sin 0 = 0

sin 30 = 1/2

sin 45 = 1/\sqrt{2}

sin 60 = \sqrt{3} /2

sin 90 = 1

Thus, we see  that value of sin is increasing from 0 to 90

now lets see value of sin from 90 to 180

sin 90 = 1

sin 120 = \sqrt{3} /2

sin 135 = 1/\sqrt{2}

sin 150 = 1/2

sin 180 = 0

Thus, we see  that value of sin is decreasing from 90 to 180.

8 0
3 years ago
What is the range of the function f(x) = 3x2 + 6x – 8?
ikadub [295]
The range of the function f(x) = 3x^2 + 6x - 8 is <span>{y|y ≥ –11}</span>
8 0
3 years ago
Read 2 more answers
Every morning, Katy goes running along a trail in a nearby park. Over the past 2 weeks, she has run 43.4 miles. How far does she
Andreas93 [3]

Answer:

Multiply 43.4 times 2

Step-by-step explanation:

4 0
3 years ago
How to find vertical and horizontal asymptotes of polynomials?
guajiro [1.7K]
Vertical asymptotes are when y tends to infinity, which in other words means you need a fraction where you're dividing by zero. So to find the vertical asymptotes, solve the denominator of the fraction and the solutions are the asymptotes since that is where it will be dividing by zero.

Horizontal asymptotes are the opposite and is where x tends to infinity -- This can be done by dividing through with the xs still there, since you are effectively just looking at multiples of infinity and infinity squared and so on. When you have an x to the power you can forget about all the other x's on the same half of the fraction, since infinity squared is infinitely bigger than infinity - yes it's abstract and a bit stupid I know.
If the degree of the polynomial on the denominator is larger than the numerator, there is an asymptote at y=0 (since the bottom becomes infinitely larger than the top). If it is lower than the numerator, you have to divide through by long division and you end up with an oblique asymptote i.e. an asymptote where the dotted line would follow a linear equation e.g. y=x

For example
f(x)= \frac{6x^2-3x+4}{2x^2-8}

The vertical asymptote can be found by solving 2x^2-8=0 i.e. x=+-2 so our vertical asymptotes are at 2 and -2.

The horizontal asymptote, think of all the x's as infinity. SInce there are x^2s, we dont need to worry about the numbers or the other x's
Therefore we are left with 6x^2/2x^2, which gives us 3. Therefore our horizontal asymptote would be at y=3.
7 0
3 years ago
I need help with this question!
ElenaW [278]

Answer:

True

Step-by-step explanation:

(x,y) becomes (-x,-y)

7 0
3 years ago
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