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Ray Of Light [21]
1 year ago
10

Choose the correct reason for the given statementsStatements:2. CD≅ AB3. CD≅ CE4. ∠E ≅ ∠CDE5. ∠A ≅ ∠CDE6. ∠A ≅ ∠E

Mathematics
1 answer:
White raven [17]1 year ago
8 0

One of the properties of a parallelogram is that its opposite sides are parallel and congruent.

Segment AB and CD are opposite sides of the parallelogram and is therefore, congruent.

Therefore, the reason for CD≅ AB is: "Opposite sides of a parallelogram/rhombus/rectangle/square are congruent."

For the next statement, since CD≅AB and AB≅CE, then by Transitive Property, CD≅CE.

Since CD and CE are sides of a triangle and are congruent as stated in Statement 3, then ∠E ≅ ∠CDE because in a triangle, angles opposite of congruent sides are congruent.

In addition, we can say that ∠A ≅ ∠CDE because parallel lines (AB and CD) cut by a transversal (AE) form congruent corresponding angles.

Lastly, since ∠A ≅ ∠CDE and ∠CDE ≅ ∠E, we can say that ∠A ≅ ∠E by Transitive Property.

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Answer:

9 years old.

Step-by-step explanation:

Since the ages of all of these students are being represented in relation to the middle student's age then we can create formulas for each student and then apply them to the formula for the sum of their ages and solve for the middle child's age (M) like so... (oldest child's age is represented by variable O and youngest child's age is represented by variable Y)

O = M + 6

Y = M - 3

30 = (M+6) + M + (M-3)  ... combine like terms

30 = 3M + 3  ... subtract 3 from both sides

27 = 3M  ... divide both sides by 3

9 = M

Now we know that the middle child is 9 years old.

6 0
3 years ago
Evaluate -(3-6)(33).
kirill115 [55]

\longrightarrow{\green{  99 }} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

- (3 - 6)(33)

=\:  - ( - 3)(33)

=\:   3 \times 33

(∵ -  \times  -  =  + )

=\: 99

<h3><u>Note</u>:-</h3>

\sf\pink{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♨}}}}}

7 0
3 years ago
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8 0
3 years ago
Please help! It's easy
mixer [17]

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$V=\frac{4}{3} \times \pi \times\frac{1}{64}

$V=\frac{1}{48}  \pi unit³

The volume of the sphere is \frac{1}{48} \pi\  \text{unit}^3.

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3 years ago
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