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Olenka [21]
3 years ago
5

Pls help I really need the answer right now​

Mathematics
1 answer:
Andrews [41]3 years ago
7 0
Take a more clear picture bc the words are way too blurry love.
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HELP ME PLZZZZZ Now class test
Airida [17]

Answer: 0.59 cents per a pounds =y

Step-by-step explanation:I dont know if this is what you are talking about

7 0
3 years ago
Keisha solved the following equation: 4x − 2x + 8 = 6(x + 4) Step Work Justification 1 2x + 8 = 6(x + 4) Combine like terms 2 2x
kolbaska11 [484]

4x - 2x + 8 = 6(x + 4)   Given

(4x - 2x) + 8 = 6(x + 4)

2x + 8 = 6(x + 4)     Combine like terms

2x + 8 = (6)(x) + (6)(4)

2x + 8 = 6x + 24    Distributive Property

2x - 6x + 8 = 6x - 6x + 24

-4x + 8 = 24      Subtraction Property of Equality

-4x + 8 - 8 = 24 - 8

-4x = 16    Subtraction Property of Equality

-4x : (-4) = 16 : (-4)

x = -4       Division Property of Equality

4 0
3 years ago
Simplify without the absolute value |x+3| ; if x>2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

8 0
3 years ago
Can someone give me three possible solutions?
astraxan [27]
X= 1 2 3 that will be the possible solution
4 0
3 years ago
Find the value of y for the given value of x.
tia_tia [17]
X=30 in the first one and x=-15 in the second one
5 0
3 years ago
Read 2 more answers
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