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Alina [70]
1 year ago
10

Can you please help me out

Mathematics
1 answer:
aniked [119]1 year ago
6 0

In order to solve this question, we need to find the area of the yellow ring and the total area. The area of the yellow ring is equal to the area of the outer ring minus the area of the red circle, that is

\begin{gathered} A_{\text{yellow}}=\pi4^2-\pi1^2 \\ A_{\text{yellow}}=16\pi-\pi \\ A_{\text{yellow}}=15\pi \\ A_{\text{yellow}}=47.124 \end{gathered}

and the total area is the area of the entire square, that is

\begin{gathered} A_{\text{total}}=10^2 \\ A_{\text{total}}=100 \end{gathered}

Then, the probability that the dart is within the yellow outer ring is given by

\begin{gathered} P(\text{inside yellow ring)=}\frac{A_{yellow}}{A_{total}} \\ P(\text{inside yellow ring)=}\frac{47.124_{}}{100} \end{gathered}

then by rounding the numetaror to the nearest whole number , the answer is

P(\text{inside yellow ring)=}0.47

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Answer: Yes, this is true but it can be a different answer.

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3 years ago
How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo
kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

s = \frac{d}{t}

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so s = 299,792.458

(a) San Francisco (about 500km)

Find t when d = 500. So

s = \frac{d}{t}

299,792.458 = \frac{500}{t}

299,792.458t = 500

t = \frac{500}{299,792.458}

t = 0.0017s

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when d = 10,000. So

s = \frac{d}{t}

299,792.458 = \frac{10,000}{t}

299,792.458t = 10,000

t = \frac{10,000}{299,792.458}

t = 0.033s

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when d = 400,000. So

s = \frac{d}{t}

299,792.458 = \frac{400,000}{t}

299,792.458t = 400,000

t = \frac{400,000}{299,792.458}

t = 1.334s

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that d = 44,879,361.3. So:

s = \frac{d}{t}

299,792.458 = \frac{44,879,361.3}{t}

299,792.458t = 44,879,361.3

t = \frac{44,879,361.3}{299,792.458}

t = 149.7s

It takes 149.7s for the light to reach Venus.

3 0
3 years ago
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Answer:

Each student would get 36 candies is their goddy bag.

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Log 10(x + 3) – log 10(x-3) = 1
nadezda [96]

Answer:33/9

Step-by-step explanation:

Log10(x+3)-Log10(x-3)=1

Log10((x+3)/(x-3))=1

(x+3)/(x-3)=10^1

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Cross multiply

x+3=10(x-3)

Open brackets

x+3=10x-30

Collect like terms

10x-x=30+3

9x=33

Divide both sides by 9

9x/9=33/9

x=33/9

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4 years ago
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The slope of the line is 7 because it is a slope
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