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IceJOKER [234]
3 years ago
12

Maria bought a 30 pound bag of dog food. In the first month her dog ate ate 12 2/5 pounds of dog food. In the second month her d

og ate 11 4/5 pounds of dog food. How much dog food was remaining in the bag at the end of the two months?
Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

24 1/5

Step-by-step explanation:

First you add 12 2/5 + 11 4/5 and that leaves you with 23 6/5 simplify it into <u>24 1/5 </u>and you get your answer!

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Please help I will mark BRAINLIEST
jolli1 [7]

answer of inches which can contain molly is=32

7 0
4 years ago
PLEASE HELP!!!!! 1.) Line a passes through points (-2, 1) and (2, 9). Write an equation in slope intercept form that is parallel
emmasim [6.3K]

Answer:

y=2x

Step-by-step explanation:

compute the slope  first-

(-2,1) and (2,9)

m = 9-1/2-(-2) = 8/2+2= 8/4 = 2

knowing the slope take a given point  and substitute  it's x and y values into the equation to solve for 'b' the y-intercept-

y = mx + b,

1 = 2(-2) + b,

1 = -4+ b,

b = 5

our  equation is  y = 2x + 5

if you want an equation parallel  to the line  it  has to have the same slope. Take y = 2x

3 0
3 years ago
Read 2 more answers
Use Stokes' Theorem to evaluate |c F * dr where C is oriented counterclockwise as viewed from above.F(x, y, z) = xyi + 5zj + 7yk
Hunter-Best [27]

Compute the curl of \vec F:

\vec F(x,y,z)=xy\,\vec\imath+5z\,\vec\jmath+7y\,\vec k\implies\nabla\times\vec F(x,y,z)=2\,\vec\imath-x\,\vec k

By Stoke's theorem, the (line) integral of \vec F along C is equivalent to the (surface) integral (or flux) of \nabla\times\vec F across S, the oriented surface with boundary C.

Take S to be the part of the plane x+z=3 within the cylinder x^2+y^2=144. Parameterize S by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(3-u\cos v)\,\vec k

with 0\le u\le12 and 0\le v\le2\pi. Take the normal vector to S to be

\vec s_u\times\vec s_v=u\,\vec\imath+u\,\vec k

Then the integral is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^{12}(2\,\vec\imath-u\cos v\,\vec k)\cdot(u\,\vec\imath+u\,\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^{12}(2u-u^2\cos v)\,\mathrm du\,\mathrm dv=\boxed{288\pi}

8 0
3 years ago
Describe the main parts of a proof.
Afina-wow [57]

(stolen)

The most common form of explicit proof in highschool geometry is a two column proof consists of five parts: the given, the proposition, the statement column, the reason column, and the diagram (if one is given).

3 0
3 years ago
Read 2 more answers
Enrollment in a school has grown exponentially since the school opened. Below is a graph depicting this growth. Determine the av
tresset_1 [31]

Answer:

2.5

Step-by-step explanation:

The average rate of the function f(x) from x=a to x=b is given by:

\frac{f(b)-f(a)}{b-a}

From the question, the exponential function goes through (0,30) and (20,80).

This implies that f(0)=30 and f(20)=80

Therefore the average rate of change from x = 0 to x = 20 is

=\frac{f(20)-f(0)}{20-0}

=\frac{80-30}{20}

=\frac{50}{20}=2.5

The second choice is correct

4 0
3 years ago
Read 2 more answers
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