From the diagram above you can see that points A and B have coordinates (8,0) and (-4,6), respectively.
The equation of the line passing through the pointa A and B is:
Then
Answer:
10. Use graphing to find the solutions to the system of equations. - x² + y = 1 -x+y=2
1 answer:
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Answer:
Geometric probability of an object hitting a circular hole is 0.0245.
Step-by-step explanation:
We have given,
A board of size 48 by 24 inch. There is a circular hole in the board having diameter 6 inches.
So,
Area of a board = 48 × 24 = 1152 square inches
And area of circular hole = π×r² {where r = diameter/2 = 6 / 2 = 3 inches}
Area of circular hole = π×3² = 9π = 28.27 square inches
Now, we need to find the geometric probability of an object will hit the circle.
Geometric probability = Area of circular hole / Area of board
Geometric probability =
Geometric probability = 0.0245
hence geometric probability of an object hitting a circular hole is 0.0245.
Answer:
y = 5x - 4
for the x values..
y = -4
y = 1
y = 6
Step-by-step explanation:
Answer:
Hence proved triangle ADE ≅ triangle BCE by Side Angle Side congruent property.
Step-by-step explanation:
Given:
AD ⊥ AB CD
BC ⊥ AB CD
AD = BC
∴ ∠ A = ∠ B = ∠ C = ∠ D =90°
∠ EDC = ∠ ECD
Solution
∠ C = ∠ BCE + ∠ ECD⇒ equation 1
∠ D = ∠ ADE + ∠ EDC⇒ equation 2
∠ C = ∠ D (given)
Substituting equation 1 and 2 in above equation we get
∠ BCE + ∠ ECD = ∠ ADE + ∠ EDC
But ∠ EDC = ∠ ECD (given)
∴ ∠ ADE = ∠ BCE
ED = EC (∵ base angles are same triangle is isosceles triangle)
Now, In Δ ADE and Δ BCE
AD =BC
∠ ADE = ∠ BDE
ED = EC
∴ By Side Angle Side congruent property
Δ ADE ≅ Δ BCE