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3 years ago

Hi, I am taking a test and really need help...... This is worth 19 points please help!!!

Mathematics

2 answers:

OlgaM077 [116]3 years ago

4 0

I believe the correct option would be the 1st option because I just took the test and I got this correct! Hope this helps :)

timurjin [86]3 years ago

3 0

Answer:

Step-by-step explanation:

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A package of 30 Oreos cost $3.60. Kennedy says the unit rate is 0.12. Mason says the unit rate is 8.33. Who is right?

Alekssandra [29.7K]

Answer:

$360 \div 30 = 12$

Step-by-step explanation:

so Kennedy is right

8 0

2 years ago

Can some one help me set up an equation out of these word problems? PLEASE HELP!!!

Elanso [62]

1: 2/5=emails 3.6hrs=emails, 3.6=2/5 5-2=3 3.6•3=__hours of work

2. 294+83=$__

3. 3•x=hw 64/4=__•3=__hrs on math

4. Idk sorry

Sorry if some of these are wrong but I'm pretty sure there right.

5 0

3 years ago

Read 2 more answers

Please Hurryyy

Helga [31]

The measure of angle J is 19.8°, and the correct option is D.

<h3>What is the formula of cosine?</h3>

The law of cosine or cosine rule in trigonometry is a relation between the side and the angles of a triangle. Suppose a triangle with sides a, b, c and with angles cosC.

The following formula is used to find the angle j is;

$\rm j^2 = h^2 + i^2 -2hicosC$

Triangle HIJ has side lengths h=12, i = 17, j = 7.

Substitute all the values in the formula;

$\rm j^2 = h^2 + i^2 -2hicosJ\\\\(7)^2=(12)^2+(17)^2-2 \times 12 \times 17 cosJ\\\\49=144+289-408cosJ\\\\144+289 -49 =408cosJ\\\\384 =408cosJ\\\\cosJ=\dfrac{384}{408}\\\\cosj = 0.94\\\\J =cos^{-1}(0.94)\\\\J=19.8$

Hence, the measure of angle J is 19.8°, and the correct option is D.

Learn more about law cosine here;

brainly.com/question/17289163

#SPJ1

3 0

1 year ago

Six identically shaped place mats, marked a, b, c, d, e and f, are piled neatly in a stack. how many arrangements are possible i

Sedaia [141]

6
1. A, b, c
2. A, b, d
3. A, b, e
4. C, a, b
5. D, a, b
6. E, a, b

Hope I helped!

5 0

3 years ago

Please help ASAP!

Kruka [31]

First, recall that

$\sin(-\theta)=-\sin\theta$

So if $\sin(-\theta)=\dfrac15$ , then $\sin\theta=-\dfrac15$ .

Second,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

We know that $\tan\theta>0$ and $\sin\theta$ , which means we should also have $\cos\theta$ .

Third,

$\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}$

but as we've already shown, we need to have $\cos\theta$ , so we pick the negative root.

Finally,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}\iff\dfrac6{\sqrt{12}}=\dfrac{-\frac15}{\cos\theta}\implies\cos\theta=-\dfrac1{5\sqrt3}$

Unfortunately, none of the given answers match, so perhaps I've misunderstood one of the given conditions... In any case, this answer should tell you everything you need to know to find the right solution from the given options.

6 0

3 years ago