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2 years ago

What is the circumference if the diameter is 21in and pi is 22/7

Mathematics

1 answer:

Ede4ka [16]2 years ago

6 0

Answer:

66 in

Explanation:

the circumference can be calculated as:

$C=d\cdot\pi$

Where d is the diameter and π is 22/7.

So, replacing the values, we get:

$C=21\cdot\frac{22}{7}=\frac{21\cdot22}{7}=\frac{462}{7}=66\text{ in}$

Therefore, the circumference is 66 in.

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who else has trouble with math and then gets ridiculed and made fun of by teachers and adults and other, smarter students and th

melomori [17]

Answer:

'''who else has trouble with math and then gets ridiculed and made fun of by teachers and adults and other, smarter students and then just wants to die?''

YES!

3 0

3 years ago

Read 2 more answers

Section J in an arena has 20 rows.Each row has 15 seats.All tickets cost $18 each.If all the seats are sold how much money will

bekas [8.4K]

Answer:Total amount of money collected for arena J = $5400

Step-by-step explanation:

Section J in an arena has 20 rows.

Each row has 15 seats. This can also means that section J has 20 rows and 15 columns. The rows and column form a rectanglar shape. This means that the total number of seats would be number of rows × number of columns

= 15 × 20 = 300 seats

All tickets cost $18 each. If all the seats are sold, that means that each seat cost $18 each.

Total amount of money collected for arena J would be total number of seats × the cost per seat.

Total amount of money collected for arena J = 300 × 18 = $5400

5 0

4 years ago

How does one integrate the following:

grin007 [14]

Consider substituting $u=4+xy$ , so that $\mathrm du=x\,\mathrm dy$ . Then

$\displaystyle\int_{x=a}^{x=b}\int_{y=a}^{y=b}\frac x{(4+xy)^2}\,\mathrm dy\,\mathrm dx=\int_{x=a}^{x=b}\int_{u=4+ax}^{u=4+bx}\frac1{u^2}\,\mathrm du\,\mathrm dx$
$=\displaystyle\int_{x=a}^{x=b}\left(-\frac1u\right)\bigg|_{u=4+ax}^{u=4+bx}\,\mathrm dx$
$=\displaystyle\int_{x=a}^{x=b}\left(\frac1{4+ax}-\frac1{4+bx}\right)\,\mathrm dx$

Then by similar substitutions, you can easily find that you end up with

$\dfrac1a\ln|4+ax|-\dfrac1b\ln|4+bx|\bigg|_{x=a}^{x=b}$
$=\dfrac1a\ln|4+ab|-\dfrac1b\ln|4+b^2|-\dfrac1a\ln|4+a^2|+\dfrac1b\ln|4+ab|$
$=\dfrac1a\ln\left|\dfrac{4+ab}{4+a^2}\right|+\dfrac1b\ln\left|\dfrac{4+ab}{4+b^2}\right|$

Of course, this all assumes that the integrand is continuous over the domain of integration, which would require that $a,b$ are chosen such that $xy\neq-4$ for any $(x,y)\in[a,b]^2$ . If in particular $ab>-4$ , then we can write

$=\dfrac1a\ln\dfrac{4+ab}{4+a^2}+\dfrac1b\ln\dfrac{4+ab}{4+b^2}$

and you can combine the logarithms if you like as

$=\ln\sqrt[a]{\dfrac{4+ab}{4+a^2}}+\ln\sqrt[b]{\dfrac{4+ab}{4+b^2}}$
$=\ln\left(\sqrt[a]{\dfrac{4+ab}{4+a^2}}\sqrt[b]{\dfrac{4+ab}{4+b^2}}\right)$

7 0

3 years ago

PLEASE ANSWER <img src="https://tex.z-dn.net/?f=92.3%20%5Ctimes%2073.2" id="TexFormula1" title="92.3 \times 73.2" alt="92.3

Ierofanga [76]

6,756.36

Is the answer to thing question hope this helps

3 0

3 years ago

Read 2 more answers

It takes 56 hours to build three bed frames, a bookcase, and four chairs. It takes 66 hours to build four bed frames and six cha

Sladkaya [172]

Answer:

12 hours

Step-by-step explanation:

Let the times be:

Bed frame - f
Bookcase - b
Chair - c

We have following equations:

3f + b + 4c = 56
4f + 6c = 66
2f + 7b + 3c = 89

Simplify the second equation and subtract from the third one:

7b = 89 - 33
7b = 56
b = 8

Replacing b in the first and third equations:

3f + 4c = 48
2f + 3c = 33

Four times the bottom equation and subtract the triple the one above:

8f - 9f = 4(33) - 3(48)
f = 12

It takes 12 hours to build one bed frame

6 0

3 years ago