Ask question

Ask question

All categories

3 years ago

5

Without graphing, tell if this pair is on the graph 5x-3y=14, (-1,-6)

1 answer:

Nutka1998 [239]3 years ago

5 0

I don’t think you have it for me I just did

You might be interested in

Two cars leave a city and head in the same direction. After 5 hours, the faster car is 20 miles ahead or

Rainbow [258]

Answer:

49 & 60

Step-by-step explanation:

294+66=362(miles) divided by 6( hours) = 60

6 0

3 years ago

Read 2 more answers

Please help!!<br> im not sure how to find the answer

Sophie [7]

Answer:

93

Step-by-step explanation:

Add: 67+41+91+68=267

Subtract: 360-267=93

Hope this helps

3 0

3 years ago

Factor -y - 8.<br> Please hurry it’s timed

max2010maxim [7]

Answer:

need more info

Step-by-step explanation:

3 0

3 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

How is 2.32 written in words

kati45 [8]

Your answer is two point thirty-two hundreths hope this helps have a nice day. >q<

6 0

3 years ago