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storchak [24]
3 years ago
6

What is a correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9?

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

<em>-12 + 20x ≥ -6x + 9</em>

<em>Fourth choice</em>

Step-by-step explanation:

<u>Inequalities</u>

We are given the inequality:

-4(3 - 5x) ≥ -6x + 9

Solving the inequality implies having x isolated on one of the sides.

We must start by removing the parentheses. It will be done by multiplying -4 by (3 - 5x). Since this operation doesn't imply multiplying all the inequality by a negative number, the sign won't be flipped:

-4*3 - (-4)5x ≥ -6x + 9

Multiplying:

-12 + 20x ≥ -6x + 9

Fourth choice

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Answer:

Step-by-step explanation:

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2 years ago
What is the value of n?<br><br> 5/2+2/3+n=1/6
d1i1m1o1n [39]
<span>15/6  + 4/6 +n = 1/6
18/6 = n
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3 years ago
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What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x4+5 ?
Valentin [98]
Attached a solution and showed work.

8 0
3 years ago
Anyone help with math??
Triss [41]

Answer:

I can maybe!

OK, sorry it took me so long I wanted to make sure I gave you the best answer I could so I had to think a little. Anyway. If I had to pick one I would choose...

D. The value of g(x) is determined by the value of h times x.

I really hope this helps! I tried my best!




4 0
3 years ago
A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is
scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

\bar X_{1}=360000 represent the mean for the downtown restaurant

\bar X_{2}=340000 represent the mean for the freeway restaurant

s_{1}=50000 represent the sample standard deviation for downtown

s_{2}=40000 represent the sample standard deviation for the freeway

n_{1}=36 sample size for the downtown restaurant

n_{2}=36 sample size for the freeway restaurant

t would represent the statistic (variable of interest)

\alpha=0.05 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis:\mu_{1}\leq \mu_{2}

Alternative hypothesis:\mu_{1} > \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level\alpha=0.05 and \alpha/2=0.025 we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is t_{1-\alpha/2}=1.66

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

p_v =P(t_{70}>1.874)=0.033

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0
2 years ago
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